检查 C# 中的任何 int 类型？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/321139/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Check for any int type in C#?
提问by Eric W
I have a function that, among other things, takes in an object and a Type, and converts the object into that Type. However, the input object is often a double, and the type some variation of int (uint, long, etc.). I want this to work if a round number is passed in as a double (like 4.0), but to throw an exception if a decimal is passed in (4.3). Is there any more elegant way to check if the Type is some sort of int?
我有一个函数，除其他外，它接收一个对象和一个类型，并将对象转换为该类型。但是，输入对象通常是双精度型，并且类型是 int 的一些变体（uint、long 等）。如果将整数作为双精度数（如 4.0）传入，我希望它可以工作，但如果传入小数（4.3）则抛出异常。有没有更优雅的方法来检查 Type 是否是某种 int？
if (inObject is double && (targetType == typeof (int)
|| targetType == typeof (uint)
|| targetType == typeof (long)
|| targetType == typeof (ulong)
|| targetType == typeof (short)
|| targetType == typeof (ushort)))
{
double input = (double) inObject;
if (Math.Truncate(input) != input)
throw new ArgumentException("Input was not an integer.");
}
Thanks.
谢谢。
采纳答案by Amy B
This seems to do what you ask. I have only tested it for doubles, floats and ints.
这似乎符合您的要求。我只测试了双打、浮点数和整数。
public int GetInt(IConvertible x)
{
int y = Convert.ToInt32(x);
if (Convert.ToDouble(x) != Convert.ToDouble(y))
throw new ArgumentException("Input was not an integer");
return y;
}
回答by PolyglotProgrammer
You should be able to use a combination of Convert.ToDecimal and x % y, I would have thought, where y = 1 and checking the result ==0;
您应该能够使用 Convert.ToDecimal 和 x % y 的组合，我原以为，其中 y = 1 并检查结果 ==0；
回答by Ricardo Villamil
int intvalue;
if(!Int32.TryParse(inObject.ToString(), out intvalue))
throw InvalidArgumentException("Not rounded number or invalid int...etc");
return intvalue; //this now contains your value as an integer!
