java 如何验证在编辑文本中输入的数字？- 安卓
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How to validate a number entered in the edittext? - android
提问by kumareloaded
well am able to validate an edittext when its empty using the below code
当编辑文本为空时，可以使用以下代码验证它
EditText a = (EditText) findViewById(R.id.edittext1);
if ((a.getText().toString().equals(""))
{
Toast.makeText(getApplicationContext(), "value is empty", 0).show();
}
the edittextinput type is set as number.
所述的EditText输入类型被设定为编号。
now i want to validate the number entered.
现在我想验证输入的数字。
for example the range of number to be entered should be between 15 to 25.
例如，要输入的数字范围应在 15 到 25 之间。
if the number is below 15 or above 25 it should show Out of Range
如果数字低于 15 或高于 25，则应显示超出范围
help me out! :)
帮帮我！:)
回答by thomasg
You can do something like that:
你可以这样做：
final int value = Integer.valueOf(a.getText().toString());
if (value < 15 || value > 25) {
// do what you want
}
回答by Subir Kumar Sao
Parse the value to Integer or Float and do your validation.
将值解析为 Integer 或 Float 并进行验证。
Integer.parseInt(a.getText())
回答by Jave
If you know that the value entered is a number you can first parse it using either:int val = Integer.parseInt(a.getText());
or if it is a float:float val = Float.parseFloat(a.getText());.
如果您知道输入的值是一个数字，您可以首先使用以下任一方法解析它：int val = Integer.parseInt(a.getText());
或者如果它是一个浮点数：float val = Float.parseFloat(a.getText());。
Then you can just do a comparison: if( val < min || val > max ) //show message;
然后你可以做一个比较：if( val < min || val > max ) //show message;
回答by Abhijeet Sharma
You can use this method to check decimal number is valid or not valid:
您可以使用此方法来检查十进制数是否有效：
public boolean isValidDecimalNumber(EditText editText) {
return !TextUtils.isEmpty(editText.getText().toString().trim()) && !editText.getText().toString().trim().equalsIgnoreCase(".");
}
