javascript 在 jQuery AJAX 后输出中读取 JSON 数据
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Reading JSON data in jQuery AJAX post output
提问by sam fisher
I have the code below which i am passing through json to jquery.
我有下面的代码，我将通过 json 传递给 jquery。
$string['msg']['1']['Name'] = "John Doe";
$string['msg']['1']['Said'] = "Hello there";
$string['msg']['2']['Name'] = "Jane King";
$string['msg']['2']['Said'] = "Hello there";
$string['errors']['1']['Person'] = "Jane King";
$string['errors']['1']['type'] = "Wrong Screwdriver";
$string['errors']['2']['Person'] = "John Doe";
$string['errors']['2']['type'] = "Wrong Spanner";
The JSON output is below:
JSON 输出如下：
{"msg":{"1":{"Name":"John Doe","Said":"Hello there"},"2":{"Name":"Jane King","Said":"Hello there"}},"errors":{"1":{"Person":"Jane King","type":"Wrong Screwdriver"},"2":{"Person":"John Doe","type":"Wrong Spanner"}}}
This is the ajax code that is retreiving the json.
这是检索 json 的 ajax 代码。
$.ajax({
dataType : 'json',
url: 'polling.php',
type: 'post',
data: 'id=1',
success: function(data) {
//read json
});
I am trying to read all 'msg' in order of number.. 1, 2.. and get 'Name' and 'Said' values for each.
我正在尝试按数字顺序读取所有“味精”.. 1、2.. 并为每个获取“名称”和“说”值。
Then do the same for 'errors'
然后对“错误”执行相同的操作
but i cant correctly retrieve any values
但我无法正确检索任何值
回答by Satpal
As per your given output:
根据您给定的输出：
Try this:
试试这个：
$(function(){
var data = {"msg":{"1":{"Name":"John Doe","Said":"Hello there"},"2":{"Name":"Jane King","Said":"Hello there"}},"errors":{"1":{"Person":"Jane King","type":"Wrong Screwdriver"},"2":{"Person":"John Doe","type":"Wrong Spanner"}}};
$.each(data.msg, function(index, value) {
alert(index + ': ' + value.Name);
});
});
回答by Jayendra
Demo Link
演示链接
var data = {"msg":{"1":{"Name":"John Doe","Said":"Hello there"},"2":{"Name":"Jane King","Said":"Hello there"}},"errors":{"1":{"Person":"Jane King","type":"Wrong Screwdriver"},"2":{"Person":"John Doe","type":"Wrong Spanner"}}};
$.each(data['msg'], function(key, element){
console.log(key+' : '+element['Name']);
});
$.each(data['errors'], function(key, element){
console.log(key+' : '+element['Person']);
});
