JavaScript 下一个兄弟？
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JavaScript next sibling?
提问by JasonS
Could someone show me how to loop through the anchor tags within a div and find the next sibling?
有人可以告诉我如何遍历 div 中的锚标记并找到下一个兄弟姐妹吗？
I have this so far.
到目前为止我有这个。
var menu = document.getElementById('menu');
var links = menu.getElementsByTagName('a');
How do I loop through the links? Can I use .nextSiblingto find if the next sibling is a div?
如何遍历链接？我可以.nextSibling用来查找下一个兄弟姐妹是否是 div 吗？
回答by Tim Down
The nextSiblingproperty of DOM nodes works perfectly in all browsers and does exactly what you'd expect. If there is no next sibling, it returns null.
nextSiblingDOM 节点的属性在所有浏览器中都能完美运行，并且完全符合您的预期。如果没有下一个兄弟，则返回null。
Iterating over a NodeList(which is what getElementsByTagNamereturns) is identical to iterating over an array using a standard forloop. The following will iterate over the links and alert each time it finds one whose next sibling is a <div>:
迭代 a NodeList（这是getElementsByTagName返回的内容）与使用标准for循环迭代数组相同。以下将遍历链接并在每次找到下一个兄弟是 a 的链接时发出警报<div>：
var menu = document.getElementById('menu');
var links = menu.getElementsByTagName('a');
// Iterate over the links
for (var i = 0, len = links.length, link; i < len; ++i) {
link = links[i];
if (link.nextSibling && link.nextSibling.nodeName == "DIV") {
alert("Next sibling is DIV! " + link.innerHTML);
}
}
Note that in non-IE browsers, whitespace between elements in HTML is considered a text node. You may want to ignore these whitespace nodes when considering what the next sibling of each link is. The following will do that:
请注意，在非 IE 浏览器中，HTML 中元素之间的空白被视为文本节点。在考虑每个链接的下一个兄弟节点是什么时，您可能希望忽略这些空白节点。以下将做到这一点：
function isWhitespace(node) {
return node.nodeType == 3 && /^\s*$/.test(node.data);
}
// Iterate over the links
for (var i = 0, len = links.length, link, next; i < len; ++i) {
link = links[i];
next = link.nextSibling;
if (next && isWhitespace(next)) {
next = next.nextSibling;
}
if (next && next.nodeName == "DIV") {
alert("Next sibling is DIV! " + link.innerHTML);
}
}
回答by Alex Rashkov
for(var i=0; i<links.length; i++) {
if (links[i].nextChild.nodeName=="DIV")
alert("This is a DIV")
}
