在 Python 字符串中的最后一个分隔符上拆分？
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Splitting on last delimiter in Python string?
提问by
What's the recommended Python idiom for splitting a string on the lastoccurrence of the delimiter in the string? example:
在字符串中最后一次出现分隔符时拆分字符串的推荐 Python 习语是什么？例子：
# instead of regular split
>> s = "a,b,c,d"
>> s.split(",")
>> ['a', 'b', 'c', 'd']
# ..split only on last occurrence of ',' in string:
>>> s.mysplit(s, -1)
>>> ['a,b,c', 'd']
mysplittakes a second argument that is the occurrence of the delimiter to be split. Like in regular list indexing, -1means the last from the end. How can this be done?
mysplit接受第二个参数，即要拆分的分隔符的出现。就像在常规列表索引中一样，-1意味着最后一个。如何才能做到这一点？
采纳答案by Martijn Pieters
Use .rsplit()or .rpartition()instead:
使用.rsplit()或.rpartition()代替：
s.rsplit(',', 1)
s.rpartition(',')
str.rsplit()lets you specify how many times to split, while str.rpartition()only splits once but always returns a fixed number of elements (prefix, delimiter & postfix) and is faster for the single split case.
str.rsplit()允许您指定拆分的次数，而str.rpartition()只拆分一次但始终返回固定数量的元素（前缀、分隔符和后缀），并且对于单个拆分情况更快。
Demo:
演示：
>>> s = "a,b,c,d"
>>> s.rsplit(',', 1)
['a,b,c', 'd']
>>> s.rsplit(',', 2)
['a,b', 'c', 'd']
>>> s.rpartition(',')
('a,b,c', ',', 'd')
Both methods start splitting from the right-hand-side of the string; by giving str.rsplit()a maximum as the second argument, you get to split just the right-hand-most occurrences.
两种方法都从字符串的右侧开始拆分；通过str.rsplit()将最大值作为第二个参数，您可以只拆分最右侧的事件。
回答by ViKiG
I just did this for fun
我只是为了好玩
>>> s = 'a,b,c,d'
>>> [item[::-1] for item in s[::-1].split(',', 1)][::-1]
['a,b,c', 'd']
Caution: Refer to the first comment in below where this answer can go wrong.
注意：请参阅下面的第一条评论，此答案可能出错。
回答by Vivek Ananthan
You can use rsplit
您可以使用 rsplit
string.rsplit('delimeter',1)[1]
To get the string from reverse.
从反向获取字符串。
