php CodeIgniter - 如何从控制器返回 Json 响应
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时间：2020-08-25 18:16:54 来源:igfitidea点击:
CodeIgniter - How to return Json response from controller
提问by Bryan Learn
How do I return response from the controller back to the Jquery Javascript?
如何将控制器的响应返回给 Jquery Javascript？
Javascript
Javascript
$('.signinform').submit(function() {
$(this).ajaxSubmit({
type : "POST",
url: 'index.php/user/signin', // target element(s) to be updated with server response
cache : false,
success : onSuccessRegistered,
error: onFailRegistered
});
return false;
});
Data is returned null (blank)!
数据返回空（空白）！
function onSuccessRegistered(data){
alert(data);
};
Controller -
控制器 -
public function signin() {
$arr = array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 4, 'e' => 5);
echo json_encode( $arr );
}
回答by Cliff Richard Anfone
return $this->output
->set_content_type('application/json')
->set_status_header(500)
->set_output(json_encode(array(
'text' => 'Error 500',
'type' => 'danger'
)));
回答by Sundar
//do the edit in your javascript
$('.signinform').submit(function() {
$(this).ajaxSubmit({
type : "POST",
//set the data type
dataType:'json',
url: 'index.php/user/signin', // target element(s) to be updated with server response
cache : false,
//check this in Firefox browser
success : function(response){ console.log(response); alert(response)},
error: onFailRegistered
});
return false;
});
//controller function
public function signin() {
$arr = array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 4, 'e' => 5);
//add the header here
header('Content-Type: application/json');
echo json_encode( $arr );
}
回答by Sundar
This is not your answer and this is an alternate way to process the form submission
这不是您的答案，这是处理表单提交的另一种方式
$('.signinform').click(function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: 'index.php/user/signin', // target element(s) to be updated with server response
dataType:'json',
success : function(response){ console.log(response); alert(response)}
});
});
