C++ 将“this”指针转换为字符串
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Convert "this" pointer to string
提问by Mr. Boy
In a system where registered objects must have unique names, I want to use/include the object's thispointer in the name. I want the simplest way to create ???where:
在注册对象必须具有唯一名称的系统中，我想在名称中使用/包含对象的this指针。我想要最简单的方法来创建???：
std::string name = ???(this);
std::string name = ???(this);
回答by Nawaz
You could use string representation of the address:
您可以使用地址的字符串表示形式：
#include <sstream> //for std::stringstream
#include <string> //for std::string
const void * address = static_cast<const void*>(this);
std::stringstream ss;
ss << address;
std::string name = ss.str();
回答by Useless
You mean format the pointer itself as a string?
您的意思是将指针本身格式化为字符串？
std::ostringstream address;
address << (void const *)this;
std:string name = address.str();
Or ... yes, all the other equivalent answers in the time it took me to type this!
或者......是的，在我输入这个的时间里所有其他等效的答案！
回答by mloskot
#include <sstream>
#include <iostream>
struct T
{
T()
{
std::ostringstream oss;
oss << (void*)this;
std::string s(oss.str());
std::cout << s << std::endl;
}
};
int main()
{
T t;
}
回答by Aditya Kumar Pandey
You could use ostringstream the this pointer's address and put that ostringstream's value as string?
您可以使用 ostringstream this 指针的地址并将该 ostringstream 的值作为字符串？
回答by David Hammen
In a system where registered objects must have unique names, I want to use/include the object's this pointer in the name.
在注册对象必须具有唯一名称的系统中，我想在名称中使用/包含对象的 this 指针。
An object's address is not necessarily unique. Example: You dynamically allocate such an object, use it for a while, delete it, and then allocate another such object. That newly allocated object might well have the same the object address as the previous.
对象的地址不一定是唯一的。示例：您动态分配这样一个对象，使用它一段时间，删除它，然后再分配另一个这样的对象。新分配的对象很可能与之前的对象地址相同。
There are far better ways to generate a unique name for something. A gensym counter, for example:
有更好的方法可以为某物生成唯一的名称。一个 gensym 计数器，例如：
// Base class for objects with a unique, autogenerated name.
class Named {
public:
Named() : unique_id(gensym()) {}
Named(const std::string & prefix) : unique_id(gensym(prefix)) {}
const std::string & get_unique_id () { return unique_id; }
private:
static std::string gensym (const std::string & prefix = "gensym");
const std::string unique_id;
};
inline std::string Named::gensym (const std::string & prefix) {
static std::map<std::string, int> counter_map;
int & entry = counter_map[prefix];
std::stringstream sstream;
sstream << prefix << std::setfill('0') << std::setw(7) << ++entry;
return sstream.str();
}
// Derived classes can have their own prefix. For example,
class DerivedNamed : public Named {
public:
DerivedNamed() : Named("Derived") {}
};
