C# 断言数组在 Visual Studio 2008 测试框架中相等

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/897552/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-05 22:04:21  来源:igfitidea点击:

Assert that arrays are equal in Visual Studio 2008 test framework

c#visual-studio-2008unit-testing

提问by Anteru

Is there an easy way to check in a unit test that two arrays are equal (that is, have the same number of elements, and each element is the same?).

是否有一种简单的方法可以在单元测试中检查两个数组是否相等(即具有相同数量的元素,并且每个元素都相同?)。

In Java, I would use assertArrayEquals (foo, bar);, but there seems to be no equivalent for C#. I tried Assert.AreEqual(new string[]{"a", "b"}, MyFunc("ab"));, but even though the function returns an array with "a", "b" the check still fails

在 Java 中,我会使用assertArrayEquals (foo, bar);,但似乎没有 C# 的等价物。我试过了Assert.AreEqual(new string[]{"a", "b"}, MyFunc("ab"));,但即使函数返回一个带有“a”、“b”的数组,检查仍然失败

This is using Visual Studio 2008 Team Suite, with the built-in unit test framework.

这是使用带有内置单元测试框架的 Visual Studio 2008 Team Suite。

采纳答案by Anteru

It's CollectionAssert.AreEqual, see also the documentation for CollectionAssert.

它是CollectionAssert.AreEqual,另请参阅CollectionAssert文档

回答by Marc Gravell

In .NET 3.5, perhaps consider Assert.IsTrue(foo.SequenceEqual(bar));- it won't tell you at what index it differs, though.

在 .NET 3.5 中,也许考虑一下Assert.IsTrue(foo.SequenceEqual(bar));- 但是它不会告诉你它在什么索引上有所不同。

回答by Autodidact

Ok here is a slightly longer way of doing it...

好的,这是一种稍微长一点的方法......

static void Main(string[] args)
{
    var arr1 = new[] { 1, 2, 3, 4, 5 };
    var arr2 = new[] { 1, 2, 4, 4, 5 };

    Console.WriteLine("Arrays are equal: {0}", equals(arr1, arr2));
}

private static bool equals(IEnumerable arr1, IEnumerable arr2)
{

    var enumerable1 = arr1.OfType<object>();
    var enumerable2 = arr2.OfType<object>();

    if (enumerable1.Count() != enumerable2.Count())
        return false;

    var iter1 = enumerable1.GetEnumerator();
    var iter2 = enumerable2.GetEnumerator();

    while (iter1.MoveNext() && iter2.MoveNext())
    {
        if (!iter1.Current.Equals(iter2.Current))
            return false;
    }

    return true;
}

回答by Erix Xu

Class1.cs:

Class1.cs:


namespace ClassLibrary1
{
    public class Class1
    {
        Array arr1 = new[] { 1, 2, 3, 4, 5 };
        public Array getArray()
        {
            return arr1;
        }
    }
}

ArrayEqualTest.cs:

ArrayEqualTest.cs:


        [TestMethod()]
        public void getArrayTest()
        {
            Class1 target = new Class1(); 
            Array expected = new []{1,2,3,4,5}; 
            Array actual;
            actual = target.getArray();
            CollectionAssert.AreEqual(expected, actual);
            //Assert.IsTrue(expected.S actual, "is the test results");
        }

Test Success,found the error:

测试成功,发现错误:


   CollectionAssert.AreEqual failed. (Element at index 3 do not match.)