javascript SyntaxError: 在元素列表 [object Object] 之后缺少 ]
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SyntaxError: missing ] after element list [object Object]
提问by Bardelman
I got this error in firebug :
我在 firebug 中遇到了这个错误：
SyntaxError: missing ] after element list
[object Object]
for the following javascript piece of code :
对于以下 javascript 代码：
for ( var i = 0; i < 4; i++ ) {
setTimeout( function(){
closeBtn( i,'.lt400' );
// the error exactly happened in next line:
setTimeout($('#uploaded-holder').hide(), i * 300 );
}, i * 300 );
}
I don't know how a ] can be missing there.. by the way, in chrome i got this error :
我不知道 ] 怎么会在那里丢失..顺便说一下，在 chrome 中我遇到了这个错误：
Uncaught SyntaxError: Unexpected identifier
回答by JAAulde
setTimeoutexpects a function or a string of code as the first parameter. You are passing the result of the evaluation of this expression:
setTimeout需要一个函数或一串代码作为第一个参数。您正在传递此表达式的评估结果：
$('#uploaded-holder').hide()
This expression returns neither a string, nor a function. It returns a jQuery collection.
此表达式既不返回字符串，也不返回函数。它返回一个 jQuery 集合。
You want:
你要：
setTimeout(function () {
$('#uploaded-holder').hide();
}, i * 300 );
You have an odd set of code there, though, given the combination of setTimeouts and the loop. I would expect some wild oddities to come from it once this error is resolved. For example, iis not going to be what you expect in the execution of many of those internal functions...
但是，考虑到 setTimeouts 和循环的组合，您在那里有一组奇怪的代码。一旦这个错误得到解决，我预计会出现一些疯狂的奇怪现象。例如，i在执行许多这些内部功能时，不会是您所期望的......
回答by Rahul Tripathi
You may try to use this:-
你可以尝试使用这个：-
setTimeout( function ()
{ $('#uploaded-holder').hide() }, i * 300 );
instead of
代替
setTimeout($('#uploaded-holder').hide(), i * 300 );
as setTimeoutexpects a string or a function as first parameter.
因为setTimeout需要一个字符串或一个函数作为第一个参数。
回答by Sumeet Mathew
You can also try this , this also works
你也可以试试这个，这也有效
setTimeout(" $('#uploaded-holder').hide() ", i * 300 );
setTimeout(" $('#uploaded-holder').hide() ", i * 300 );
Add the first parameter within double quotes.
在双引号内添加第一个参数。
