XCODE 传递一个方法作为参数
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/10880349/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
提示：将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间：2020-09-15 00:29:33 来源:igfitidea点击:
XCODE pass a method as parameter
提问by 88fsantos
I wan't to pass a method as a parameter to another method, so it know the method to call when ends running. Is it possible?
我不想将方法作为参数传递给另一个方法，因此它知道在结束运行时要调用的方法。是否可以？
[self bringJSON:(NSString *)_passedValua:(NSObject *)anotherMethod];
回答by Vladimir
As @Daniel mentioned in comments you can use selectorfor that. Basic scheme will be the following:
正如@Daniel 在评论中提到的，您可以为此使用选择器。基本方案如下：
// Method declaration - method accept selector as parameter
- (void) bringJSON:(NSString *)_passedValua toMethod:(SEL)anotherMethod];
// Method call - create selector from method name (mind the colon in selector - it is required if your method takes 1 parameter)
[self bringJSON:jsonString toMethod:@selector(methodName:)];
// Implementation
- (void) bringJSON:(NSString *)_passedValua toMethod:(SEL)anotherMethod]{
...
if ([target respondsToSelector:anotherMethod])
[target performSelector:anotherMethod withObject:_passedValua];
}
