C# 使用 RestSharp 向 POST 请求添加 GET 参数
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Add a GET parameter to a POST request with RestSharp
提问by leninyee
I want to make a POST request to a URL like this:
我想向这样的 URL 发出 POST 请求：
http://localhost/resource?auth_token=1234
And I want to send JSON in the body. My code looks something like this:
我想在正文中发送 JSON。我的代码看起来像这样：
var client = new RestClient("http://localhost");
var request = new RestRequest("resource", Method.POST);
request.AddParameter("auth_token", "1234");
request.AddBody(json);
var response = client.Execute(request);
How can I set the auth_tokenparameter to be a GET parameter and make the request as POST?
如何将auth_token参数设置为 GET 参数并将请求设为 POST？
采纳答案by Ender2050
This should work if you 1) add the token to the resource url and 2) specify ParameterType.UrlSegment like this:
如果您 1) 将令牌添加到资源 url 并且 2) 像这样指定 ParameterType.UrlSegment，这应该可以工作：
var client = new RestClient("http://localhost");
var request = new RestRequest("resource?auth_token={authToken}", Method.POST);
request.AddParameter("auth_token", "1234", ParameterType.UrlSegment);
request.AddBody(json);
var response = client.Execute(request);
This is far from ideal - but the simplest way I've found... still hoping to find a better way.
这远非理想 - 但我找到的最简单的方法......仍然希望找到更好的方法。
回答by Der_Meister
The current version of RestSharp has a short method that makes use of a template:
当前版本的 RestSharp 有一个使用模板的简短方法：
var request = new RestRequest("resource?auth_token={token}", Method.POST);
request.AddUrlSegment("token", "1234");
Alternatively, you can add a parameter without a template:
或者，您可以添加一个没有模板的参数：
var request = new RestRequest("resource", Method.POST);
request.AddQueryParameter("auth_token", "1234);
or
或者
var request = new RestRequest("resource", Method.POST);
request.AddParameter("auth_token", "1234", ParameterType.QueryString);
