Laravel 刀片模板未渲染
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laravel blade template not rendering
提问by hello world
Getting into laravel and im trying to work with blade templating but its not rendering. All my examples are coming for the laravel documentation.
进入 laravel，我正在尝试使用刀片模板，但它没有渲染。我所有的例子都是为 laravel 文档而来的。
UPDATE
So here is my master.blade.php filelocated in resources > views > master.blade.php
更新
所以这是我的master.blade.php 文件，位于资源 > 视图 > master.blade.php
<!DOCTYPE html>
<html>
<head>
@yield('layouts.header')
</head>
<body>
<div class="container">
<div class="content">
<div class="title">Test to Laravel 5</div>
</div>
</div>
</body>
</html>
and here is my header.blade.php file located in view/layouts/
这是我的header.blade.php 文件位于 view/layouts/
@section('header')
<title>cookie monster</title>
<link href="https://fonts.googleapis.com/css?family=Lato:100" rel="stylesheet" type="text/css">
<style>
html, body {
height: 100%;
}
body {
margin: 0;
padding: 0;
width: 100%;
display: table;
font-weight: 100;
font-family: 'Lato';
}
.container {
text-align: center;
display: table-cell;
vertical-align: middle;
}
.content {
text-align: center;
display: inline-block;
}
.title {
font-size: 96px;
}
</style>
@endsection
when i try to render my page no styles are being added even tho i have inline css at the moment, because i'm just testing how blade template engine works.
当我尝试渲染我的页面时，即使我现在有内联 css，也不会添加任何样式，因为我只是在测试刀片模板引擎的工作方式。
回答by James
You want to be using @include('layouts.header')rather than @yield.
您想使用@include('layouts.header')而不是@yield.
@yieldis what you use on a master template to specify where content will go that you can then define on a child view.
@yield是您在主模板上使用的内容，用于指定内容的去向，然后您可以在子视图上定义。
@include"allows you to easily include a Blade view from within an existing view." - https://laravel.com/docs/5.1/blade
@include“允许您从现有视图中轻松包含 Blade 视图。” - https://laravel.com/docs/5.1/blade
回答by Ohgodwhy
Your layout needs to extend something. That way it can take advantage of the defined regions in your template.
你的布局需要扩展一些东西。这样它就可以利用模板中定义的区域。
@extends('master')
回答by Peter Kota
You should extend the header.blade.phpfrom master.blade.php.
Add the following line to the first line of header.blade.php
您应该扩展header.blade.phpfrom master.blade.php。将以下行添加到第一行header.blade.php
@extends('master')
Then you may edit the @yield. The yield and the section must be the same. For example:
然后你可以编辑@yield. 产量和截面必须相同。例如：
master.blade.php
master.blade.php
@yield('header')
header.blade.php(use @stopinstead of @endsection)
header.blade.php（使用@stop代替@endsection）
@section('header')
header content
@stop
pastebin.com links:
pastebin.com 链接：
回答by KoIIIeY
layout:
布局：
@yield('header')
</head>
<body>
<div class="container">
<div class="content">
@yield('content')
<div class="title">Test to Laravel 5</div>
</div>
</div>
</body>
</html>
now, you use in controller
现在，您在控制器中使用
return view('someview');
and view code
并查看代码
@extend('layout')
@section('header')
<title>cookie monster</title>
@endsection
@section('content')
bla-bla-bla, render me IN content section of layout
@endsection
and result should be
结果应该是
<!DOCTYPE html>
<html>
<head>
<title>cookie monster</title>
</head>
<body>
<div class="container">
<div class="content">
bla-bla-bla, render me IN content section of layout
<div class="title">Test to Laravel 5</div>
</div>
</div>
</body>
</html>
回答by Gus
I was facing a similar problem where:
我遇到了类似的问题，其中：
layouts/user-profile.blade.php
布局/用户配置文件.blade.php
<body>
@yield('main')
@yield('footer')
</body>
user-profile/create.blade.php
用户配置文件/create.blade.php
@extends('layouts.user-profile')
@section('main')
<!-- include a personal-info sub-section -->
@include($templateName)
@stop
@section('footer')
<script></script>
@stop
The problem was with this sub-section inheritance where the need of blade's @parentwas needed so all of the @section('footer')blocks were rendered in the @yield('footer')
问题在于这个子部分的继承需要刀片的@parent需要，所以所有的@section('footer')块都在@yield('footer')
user-profile/create/personal-info.blade.php
用户配置文件/创建/个人信息.blade.php
@section('footer')
@parent
// subsection scripts
@stop
