如何找到以开头的python列表项

How to find the python list item that start with

提问by SPy

I have the list that contains some items like:

我有包含一些项目的列表，例如：

"GFS01_06-13-2017 05-10-18-38.csv"
"Metadata_GFS01_06-13-2017 05-10-18-38.csv"

How to find the list item that start with "GFS01_"

如何找到以开头的列表项 "GFS01_"

In SQL I use query: select item from list where item like 'GFS01_%'

在 SQL 中，我使用查询： select item from list where item like 'GFS01_%'

回答by temasso

You have several options, but most obvious are:

您有多种选择，但最明显的是：

Using list comprehensionwith a condition:

使用带条件的列表理解：

result = [i for i in some_list if i.startswith('GFS01_')]

Using filter(which returns iterator)

使用filter（返回迭代器）

result = filter(lambda x: x.startswith('GFS01_'), some_list)

回答by RyanU

You should try something like this :

你应该尝试这样的事情：

[item for item in my_list if item.startswith('GFS01_')]

where "my_list" is your list of items.

其中“my_list”是您的项目列表。

回答by Senthilkumar C

If you really want the string output like this "GFS01_06-13-2017 05-10-18-38.csv","GFS01_xxx-xx-xx.csv", you could try this:

如果你真的想要这样的字符串输出“GFS01_06-13-2017 05-10-18-38.csv”，“GFS01_xxx-xx-xx.csv”，你可以试试这个：

', '.join([item for item in myList if item.startswith('GFS01_')])

Or with quotes

或者用引号

', '.join(['"%s"' % item for item in myList if item.startswith('GFS01_')])

Filtering of list will gives you list again and that needs to be handled as per you requirement then.

列表过滤将再次为您提供列表，然后需要根据您的要求进行处理。