ruby 如何在Ruby中找到除法的余数？
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How to find remainder of a division in Ruby?
提问by Shpigford
I'm trying to get the remainder of a division using Ruby.
我正在尝试使用 Ruby 获取除法的其余部分。
Let's say we're trying to divide 208 by 11.
假设我们试图将 208 除以 11。
The final should be "18 with a remainder of 10"...what I ultimately need is that 10.
决赛应该是“18 余 10”...我最终需要的是10.
Here's what I've got so far, but it chokes in this use case (saying the remainder is 0).
这是我到目前为止所得到的，但在这个用例中它令人窒息（说其余的是0）。
division = 208.to_f / 11
rounded = (division*10).ceil/10.0
remainder = rounded.round(1).to_s.last.to_i
回答by Josh Lee
The modulo operator:
模运算符：
> 208 % 11
=> 10
回答by Phrogz
If you need just the integer portion, use integers with the /operator, or the Numeric#divmethod:
如果您只需要整数部分，请将整数与/运算符或Numeric#div方法一起使用：
quotient = 208 / 11
#=> 18
quotient = 208.0.div 11
#=> 18
If you need just the remainder, use the %operator or the Numeric#modulomethod:
如果您只需要余数，请使用%运算符或Numeric#modulo方法：
modulus = 208 % 11
#=> 10
modulus = 208.0.modulo 11
#=> 10.0
If you need both, use the Numeric#divmodmethod. This even works if either the receiver or argument is a float:
如果两者都需要，请使用该Numeric#divmod方法。如果接收者或参数是浮点数，这甚至有效：
quotient, modulus = 208.divmod(11)
#=> [18, 10]
208.0.divmod(11)
#=> [18, 10.0]
208.divmod(11.0)
#=> [18, 10.0]
Also of interest is the Numeric#remaindermethod. The differences between all of these can be seen in the documentation for divmod.
同样令人感兴趣的是Numeric#remainder方法。所有这些之间的差异可以在可见的文档divmod。
回答by xinr
please use Numeric#remainderbecause mod is not remainder
请使用Numeric#remainder因为 mod 不是余数
Modulo:
模数：
5.modulo(3)
#=> 2
5.modulo(-3)
#=> -1
Remainder:
余：
5.remainder(3)
#=> 2
5.remainder(-3)
#=> 2
here is the link discussing the problem https://rob.conery.io/2018/08/21/mod-and-remainder-are-not-the-same/
这是讨论问题的链接 https://rob.conery.io/2018/08/21/mod-and-remainder-are-not-the-same/
