php 包含时找不到php类
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php class not found when it is included
提问by billaraw
I have a class in php called "SEO_URL". At a point in that class I have this
我在 php 中有一个名为“SEO_URL”的类。在那堂课的某个时刻，我有这个
$class_name = "cPath_SEO_URL";
return $class_name::href();
and I get
我得到
Fatal error: Class 'cPath_SEO_URL' not found in
...\includes\classes\seo.class.php on line 52
The thing is I have included the class on top of SEO_URL
问题是我在 SEO_URL 之上包含了这个类
include_once(/path/to/my/class);
class SEO_URL{
}
and I get that error.
我得到了那个错误。
However, when I hard-code the class on top of the class SEO_URL it works. So this works.
但是，当我在类 SEO_URL 之上对类进行硬编码时，它会起作用。所以这是有效的。
class cPath_SEO_URL{
function cPath_SEO_URL(){}
function href() { return "CPathHref"; }
}
class SEO_URL{
...
$class_name = "cPath_SEO_URL";
return $class_name::href();
...
}
and this doesn't
而这并没有
include_once(/path/to/my/class);
class SEO_URL{
...
$class_name = "cPath_SEO_URL";
return $class_name::href();
...
}
I am trying this in oscommerce.
我正在 oscommerce 中尝试这个。
Why is that?
这是为什么？
回答by billaraw
Ok, you won't believe what was the problem.
好吧，你不会相信这是什么问题。
I am used to open and close php file like this
我习惯像这样打开和关闭php文件
<?
...
?>
not
不是
<?php
?>
and the class file was without the <?php .. ?>tag but the <? ... ?>tag. I guess the environment I am working in now wanted the <?phpnot the <?only.
并且类文件没有<?php .. ?>标签而是<? ... ?>标签。我想我现在工作的环境想要的<?php不是<?唯一的。
It would load the class but it wouldn't interpret it as php.
它会加载该类，但不会将其解释为 php。
回答by rik
With
和
$class_name = "cPath_SEO_URL";
$test = new $class_name();
return $test::href();
you're making a static call on an instance. That doesn't make sense.
Instead you'll want to do
您正在对实例进行静态调用。那没有意义。
相反，你会想要做
$class_name = "cPath_SEO_URL";
return $class_name::href();
