jQuery 获取文本作为数字
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jQuery get text as number
提问by James
This code doesn't work:
此代码不起作用：
var number = $(this).find('.number').text();
var current = 600;
if (current > number){
// do something
}
HTML:
HTML：
<div class="number">400</div>
Seems there is some problem with converting text()from text-like value to number.
text()从类似文本的值转换为数字似乎存在一些问题。
What is the solution?
解决办法是什么？
回答by RoToRa
Always use parseIntwith a radix (base) as the second parameter, or you will get unexpected results:
始终使用parseInt基数（基数）作为第二个参数，否则会得到意想不到的结果：
var number = parseInt($(this).find('.number').text(), 10);
A popular variation however is to use +as a unitary operator. This will always convert with base 10 and never throw an error, just return zeroNaNwhich can be tested with the function isNaN()if it's an invalid number:
然而，一种流行的变体是+用作酉运算符。这将始终以 10 为基数进行转换并且永远不会抛出错误，只返回零NaN，isNaN()如果它是无效数字，则可以使用该函数进行测试：
var number = +($(this).find('.number').text());
回答by Trimack
myInteger = parseInt(myString);
myInteger = parseInt(myString);
It's a standard javascript function.
这是一个标准的 javascript 函数。
回答by Matt
Use the javascript parseInt method (http://www.w3schools.com/jsref/jsref_parseint.asp)
使用 javascript parseInt 方法（http://www.w3schools.com/jsref/jsref_parseint.asp）
var number = parseInt($(this).find('.number').text(), 10);
var current = 600;
if (current > number){
// do something
}
Don't forget to specify the radix value of 10 which tells parseInt that it's in base 10.
不要忘记指定 10 的基数值，它告诉 parseInt 它以 10 为底。
回答by Thizzer
var number = parseInt($(this).find('.number').text());
var current = 600;
if (current > number)
{
// do something
}
回答by Nilks
number = parseInt(number);
That should do the trick.
这应该够了吧。
回答by Tony L.
If anyone came here trying to do this with a decimal like me:
如果有人来这里试图用像我这样的小数来做到这一点：
myFloat = parseFloat(myString);
myFloat = parseFloat(myString);
If the just need an Int, that's well covered in the other answers.
如果只需要一个 Int，其他答案中已经很好地涵盖了这一点。
