正则表达式标点分割 [Python]
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Regex punctuation split [Python]
提问by dantdj
Can anyone help me a bit with regexs? I currently have this: re.split(" +", line.rstrip()), which separates by spaces.
任何人都可以帮助我使用正则表达式吗？我目前有这个: re.split(" +", line.rstrip())，用空格分隔。
How could I expand this to cover punctuation, too?
我该如何扩展它以涵盖标点符号？
采纳答案by Mister_Tom
The official Python documentation has a good example for this one. It will split on all non-alphanumeric characters (whitespace and punctuation). Literally \W is the character class for all Non-Word characters. Note: the underscore "_" is considered a "word" character and will not be part of the split here.
官方 Python 文档对此有一个很好的示例。它将拆分所有非字母数字字符（空格和标点符号）。字面上的 \W 是所有非单词字符的字符类。注意：下划线“_”被认为是一个“单词”字符，不会成为这里拆分的一部分。
re.split('\W+', 'Words, words, words.')
See https://docs.python.org/3/library/re.htmlfor more examples, search page for "re.split"
有关更多示例，请参阅https://docs.python.org/3/library/re.html，搜索页面“re.split”
回答by Ashwini Chaudhary
Using string.punctuationand character class:
使用string.punctuation和字符类：
>>> from string import punctuation
>>> r = re.compile(r'[\s{}]+'.format(re.escape(punctuation)))
>>> r.split('dss!dfs^ #$% jjj^')
['dss', 'dfs', 'jjj', '']
回答by dawg
import re
st='one two,three; four-five, six'
print re.split(r'\s+|[,;.-]\s*', st)
# ['one', 'two', 'three', 'four', 'five', 'six']
