Javascript Google Maps API v3 设置缩放级别以显示给定半径？
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Google Maps API v3 set zoom level to show a given radius?
提问by roflwaffle
I created a map where a user inputs a zipcode and a radius (miles) and I want the map to center on the point created from the zipcode and only display (roughly) the area that would be within that radius. I am creating a Circle with the radius and trying to get the map to fit to that circle. Right now it centers correctly but the area being shown is way more than the radius given.
我创建了一个地图，其中用户输入邮政编码和半径（英里），我希望地图以从邮政编码创建的点为中心，并且只显示（大致）该半径内的区域。我正在创建一个具有半径的圆并试图使地图适合该圆。现在它正确居中，但显示的区域比给定的半径大得多。
me.center_map = function(latlng, r)
{
// latlng is the point of the zipcode
var circ = new google.maps.Circle();
circ.setRadius(r * 1609.0);
circ.setCenter(latlng);
map.setCenter(latlng);
map.fitBounds(circ.getBounds());
// updates markers
google.maps.event.trigger(map,'dragend');
};
EDIT:Drew the circle that I am using. Ideally the map would be zoomed in to the area within the radius.
编辑：绘制我正在使用的圆圈。理想情况下，地图将放大到半径内的区域。
采纳答案by Alex
The call to fitBounds() will zoom to the smallest zoom level that fully contains the bounds. If you were to zoom in 1 more zoom level the radius would not be fully contained within the map.
对 fitBounds() 的调用将缩放到完全包含边界的最小缩放级别。如果您再放大 1 个缩放级别，则半径将不会完全包含在地图中。
回答by Martin Zeitler
map.setZoom(map.getZoom() + 1);
This of course depends how good the particular radius fit (in case it's not always the same)
这当然取决于特定半径的拟合程度（以防它不总是相同的）
To display the area within the circle one would need to construct a rectangle that has it's corners on the circle's perimeter and fit the map's viewport to it's bounds.
要显示圆内的区域，需要构建一个矩形，该矩形的角位于圆的周长上，并使地图的视口适合其边界。
E.g. drawing a visible circle and a transparent rectangle with same centerpoint should work as described by the op.
例如，绘制一个可见圆和一个具有相同中心点的透明矩形应该像操作描述的那样工作。
回答by Roberto Júnior
Since June 2017, the method fitBounds has a second parameter that represents the size of the padding. For those who want to remove it, you just need to pass 0.
自 2017 年 6 月以来，fitBounds 方法有第二个参数表示填充的大小。对于那些想要删除它的人，您只需要传递 0。
Map.map.fitBounds(bounds, 0);
New method signature:
新方法签名：
fitBounds(bounds:LatLngBounds|LatLngBoundsLiteral, padding?:number)
