scala 如何解析喷雾路由中的获取请求参数？
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How can I parse out get request parameters in spray-routing?
提问by Kevin Colin
This is what the section of code looks like
这是代码部分的样子
get{
respondWithMediaType(MediaTypes.`application/json`){
entity(as[HttpRequest]){
obj => complete{
println(obj)
"ok"
}
}
}
}~
I can map the request to a spray.http.HttpRequest object and I can extract the uri from this object but I imagine there is an easier way to parse out the parameters in a get request than doing it manually.
我可以将请求映射到一个 Spray.http.HttpRequest 对象，我可以从这个对象中提取 uri，但我想有一种比手动解析获取请求中的参数更简单的方法。
For example if my get request is
例如，如果我的获取请求是
http://localhost:8080/url?id=23434&age=24
I want to be able to get id and age out of this request
我希望能够从这个请求中获取 id 和 age
回答by 4lex1v
Actually you can do this much much better. In routing there are two directives: parameterand parameters, I guess the difference is clear, you can also use some modifiers: !and ?. In case of !, it means that this parameter must be provided or the request is going to be rejected and ?returns an option, so you can provide a default parameter in this case. Example:
实际上，您可以做得更好。在路由中有两个指令：parameterand parameters，我想区别很明显，您还可以使用一些修饰符：!and ?。如果是!，则表示必须提供此参数，否则请求将被拒绝并?返回一个选项，因此您可以在这种情况下提供默认参数。例子：
val route: Route = {
(path("search") & get) {
parameter("q"!) { query =>
....
}
}
}
val route: Route = {
(path("search") & get) {
parameters("q"!, "filter" ? "all") { (query, filter) =>
...
}
}
}
