如何在bash中使python脚本“可管道化”？
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How to make a python script "pipeable" in bash?
提问by gbr
I wrote a script and I want it to be pipeablein bash. Something like:
我写了一个脚本，我希望它可以在 bash 中进行管道传输。就像是：
echo "1stArg" | myscript.py
Is it possible? How?
是否可以？如何？
采纳答案by khachik
See this simple echo.py:
看到这个简单echo.py：
import sys
if __name__ == "__main__":
for line in sys.stdin:
sys.stderr.write("DEBUG: got line: " + line)
sys.stdout.write(line)
running:
跑步：
ls | python echo.py 2>debug_output.txt | sort
output:
输出：
echo.py
test.py
test.sh
debug_output.txt content:
debug_output.txt 内容：
DEBUG: got line: echo.py
DEBUG: got line: test.py
DEBUG: got line: test.sh
回答by x13n
Everything that reads from stdin is "pipeable". Pipe simply redirects stdout of former program to the latter.
从 stdin 读取的所有内容都是“可管道化的”。管道只是将前一个程序的标准输出重定向到后者。
回答by NPE
In your Python script you simply read from stdin.
在您的 Python 脚本中，您只需从stdin.
回答by tokland
I'll complement the other answers with a grepexample that uses fileinputto implement the typical behavior of UNIX tools: 1) if no file is specifie, it reads data from stdin; 2) many files can be sent as arguments; 3) -means stdin.
我将用一个grep示例来补充其他答案，该示例使用fileinput来实现 UNIX 工具的典型行为：1) 如果没有指定文件，则它从 stdin 读取数据；2) 许多文件可以作为参数发送；3)-表示标准输入。
import fileinput
import re
import sys
def grep(lines, regexp):
return (line for line in lines if regexp.search(line))
def main(args):
if len(args) < 1:
print("Usage: grep.py PATTERN [FILE...]", file=sys.stderr)
return 2
regexp = re.compile(args[0])
input_lines = fileinput.input(args[1:])
for output_line in grep(input_lines, regexp):
sys.stdout.write(output_line)
if __name__ == '__main__':
sys.exit(main(sys.argv[1:]))
Example:
例子：
$ seq 1 20 | python grep.py "4"
4
14
