Directory.Getfiles() 多搜索模式如何过滤 c#
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How can Directory.Getfiles() multi searchpattern filters c#
提问by bmurat
Possible Duplicate:
Can you call Directory.GetFiles() with multiple filters?
I have a string array:
我有一个字符串数组：
string[] pattern={"*.jpg","*.txt","*.asp","*.css","*.cs",.....};
this string pattern
这个字符串模式
string[] dizin = Directory.GetFiles("c:\veri",pattern);
How dizin variable C:\veri directories under the directory of files assign?
dizin变量C:\veri目录下的文件目录怎么赋值？
采纳答案by sa_ddam213
You could use something like this
你可以使用这样的东西
string[] extensions = { "jpg", "txt", "asp", "css", "cs", "xml" };
string[] dizin = Directory.GetFiles(@"c:\s\sent", "*.*")
.Where(f => extensions.Contains(f.Split('.').Last().ToLower())).ToArray();
Or use FileInfo.Extensionbit safer than String.Splitbut may be slower
或者使用FileInfo.Extension比使用更安全String.Split但可能更慢
string[] extensions = { ".jpg", ".txt", ".asp", ".css", ".cs", ".xml" };
string[] dizin = Directory.GetFiles(@"c:\s\sent", "*.*")
.Where(f => extensions.Contains(new FileInfo(f).Extension.ToLower())).ToArray();
Or as juharrmentioned you can also use System.IO.Path.GetExtension
或者正如juharr提到的，你也可以使用System.IO.Path.GetExtension
string[] extensions = { ".jpg", ".txt", ".asp", ".css", ".cs", ".xml" };
string[] dizin = Directory.GetFiles(@"c:\s\sent", "*.*")
.Where(f => extensions.Contains(System.IO.Path.GetExtension(f).ToLower())).ToArray();
回答by Tommaso Belluzzo
You have different alternatives.
你有不同的选择。
String[] files = Directory.GetFiles(path, "*.*", SearchOption.AllDirectories).Where(s => s.ToLower().EndsWith(".jpg") || s.ToLower().EndsWith(".txt") || s.ToLower().EndsWith(".asp"));
Or:
或者：
String[] files = Directory.GetFiles(path).Where(file => Regex.IsMatch(file, @"^.+\.(jpg|txt|asp)$"));
Or (if you don't use Linq extensions):
或者（如果您不使用 Linq 扩展）：
List<String> files = new List<String>();
String[] extensions = new String[] { "*.jpg", "*.txt", "*.asp" };
foreach (String extension in extensions)
{
String[] files = Directory.GetFiles(path, found, SearchOption.AllDirectories);
foreach (String file in files)
files.Add(file);
}
