Java 为什么“无法为 SELECT 发出 executeUpdate()”SQLException 显示?

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时间:2020-08-13 11:42:35  来源:igfitidea点击:

Why "cannot issue executeUpdate() for SELECTs" SQLException showing?

javamysqljdbc

提问by TomJ

I am working with a log in form. This code is to check the log in details from the database. I am able to log in when the provide the correct username and password, but an exception is showing. My code is below :

我正在使用登录表单。此代码用于从数据库中检查登录详细信息。我可以在提供正确的用户名和密码时登录,但显示异常。我的代码如下:

public void signin() throws ClassNotFoundException, SQLException
{
    try {
        Class.forName("com.mysql.jdbc.Driver");
        connect2 = DriverManager
      .getConnection("jdbc:mysql://localhost:3306/mysql?"
          + "user=root&password=virus");

       statement2 = connect2.createStatement();

        preparedStatement2 = connect2
      .prepareStatement("select username,password from "+t11.getText()+";");
        resultSet2 = preparedStatement2.executeQuery();
        writeResultSet(resultSet2);

        preparedStatement2.executeUpdate();
              }  
    catch (ClassNotFoundException | SQLException e) {
    throw e;
} finally {
    close1();
}
   }

private void writeResultSet(ResultSet resultSet) throws SQLException {

while (resultSet.next()) {

  String username = resultSet.getString("username");
  String password = resultSet.getString("password");
  String usr = (String)t11.getText();
  String pwd = (String)pw11.getText();

  if( t11.getText().equals(username) && pwd.equals(password))
  {
    ((Stage)b1.getScene().getWindow()).setScene(new Scene(new UserPage()));
  }
  else
  {
             //...THIS IS WHERE I WANT TO DISPLAY THE ALERT BOX
  }
}
}

private void close1() {
try {

    if (resultSet2 != null) {
    resultSet2.close();
  }

  if (statement != null) {
    statement.close();
  }

  if (connect != null) {
    connect.close();
  }
} catch (SQLException e) {

}
}

The exception is :

例外是:

java.sql.SQLException: Can not issue executeUpdate() for SELECTs
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1074)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:988)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:974)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:919)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2416)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2375)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2359)
at login.Login.signin(Login.java:159)
at login.Login.handle(Login.java:118)
at login.Login.handle(Login.java:113)

Why this exception is shown ? How can I correct it ?

为什么显示此异常?我该如何纠正?

采纳答案by axiopisty

The problem is that you're not using JDBC appropriately. Why are you invoking executeUpdatewith a select query? You might want to try executeQueryinstead. Here is an exampleof a simple SQL selection query with JDBC.

问题是您没有正确使用 JDBC。为什么要executeUpdate使用选择查询进行调用?您可能想尝试一下executeQuery下面是一个使用 JDBC 的简单 SQL 选择查询的示例

Also, be careful to not write code that could be susceptible to SQL Injection.

另外,请注意不要编写容易受到 SQL 注入影响的代码。