C++ 如何在 std::map 中找到最大的键?
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C++ How to find the biggest key in a std::map?
提问by gak
At the moment my solution is to iterate through the map to solve this.
目前我的解决方案是遍历地图来解决这个问题。
I see there is a upper_bound
method which can make this loop faster, but is there a quicker or more succinct way?
我看到有一种upper_bound
方法可以使这个循环更快,但有没有更快或更简洁的方法?
回答by GManNickG
The end:
结束:
m.rbegin();
Maps(and sets) are sorted, so the first element is the smallest, and the last element is the largest. By default maps use std::less
, but you can switch the comparer and this would of course change the position of the largest element. (For example, using std::greater
would place it at begin()
.
Maps(和sets)是有序的,所以第一个元素最小,最后一个元素最大。默认映射使用std::less
,但您可以切换比较器,这当然会更改最大元素的位置。(例如, usingstd::greater
会将它放在begin()
.
Keep in mind rbegin
returns an iterator. To get the actual key, use m.rbegin()->first
. You mightwrap it up into a function for clarity, though I"m not sure if it's worth it:
请记住rbegin
返回一个迭代器。要获取实际密钥,请使用m.rbegin()->first
. 为了清楚起见,您可能会将其包装成一个函数,但我不确定它是否值得:
template <typename T>
inline const typename T::key_type& last_key(const T& pMap)
{
return pMap.rbegin()->first;
}
typedef std::map</* types */> map_type;
map_type myMap;
// populate
map_type::key_type k = last_key(myMap);
回答by user200783
The entries in a std::map are sorted, so for a std::map m (assuming m.empty()
is false), you can get the biggest key easily: (--m.end())->first
std::map 中的条目已排序,因此对于 std::map m(假设m.empty()
为 false),您可以轻松获得最大的键:(--m.end())->first
回答by Vivek
As std::map is assosiative array one can easily find biggest or smallest key very easily. By defualt compare function is less(<) operator so biggest key will be last element in map. Similarly if someone has different requirement anyone can modify compare function while declaring map.
由于 std::map 是关联数组,因此可以很容易地找到最大或最小的键。默认比较函数是 less(<) 运算符,因此最大的键将是映射中的最后一个元素。同样,如果有人有不同的要求,任何人都可以在声明映射时修改比较函数。
std::map< key, Value, compare< key,Value > >
std::map<键、值、比较<键、值>>
By default compare=std::less
默认情况下 compare=std::less