添加用户角色到jwt,laravel 5 jwt-auth
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Add the user role to the jwt, laravel 5 jwt-auth
提问by RVandersteen
I have a laravel 5 backend that sends an jwt-token as a json response on login with jwt-auth.
我有一个 Laravel 5 后端,它在使用jwt-auth登录时发送一个 jwt-token 作为 json 响应。
Now I would like to add the user role to the jwt token that laravel sends, I tried the following way:
现在我想将用户角色添加到laravel发送的jwt令牌中,我尝试了以下方法:
This is my current controller
这是我当前的控制器
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Http\Controllers\Controller;
use JWTAuth;
use Tymon\JWTAuth\Exceptions\JWTException;
use Illuminate\Database\Eloquent\Model;
use App\User;
class AuthenticateController extends Controller
{
public function authenticate(Request $request)
{
// grab credentials from the request
$credentials = $request->only('email', 'password');
$user = User::where('email', '=', $credentials['email'])->first();
$customClaims = ['role' => $user->role];
try {
// attempt to verify the credentials and create a token for the user
if (! $token = JWTAuth::attempt($credentials, $customClaims)) {
return response()->json(['error' => 'invalid_credentials'], 401);
}
} catch (JWTException $e) {
// something went wrong whilst attempting to encode the token
return response()->json(['error' => 'could_not_create_token'], 500);
}
// all good so return the token
return response()->json(compact('token'));
}
}
?>
Is there a cleaner way to do this ?
有没有更干净的方法来做到这一点?
采纳答案by Olatunde Alex-Oni
You are currently querying for the user twice, once using the email for the purpose of getting the role and the second within the jwt::attempt()method.I would suggest reducing the queries to just one but doing the authentication {Auth::attempt($credientials)} and then
passing the retrieved user into JWT::fromUser()method, along with the custom claim. so
您目前正在查询用户两次,一次使用电子邮件获取角色,第二次使用jwt::attempt()方法。我建议将查询减少到一次,但进行身份验证 {Auth::attempt($credentials)}然后将检索到的用户JWT::fromUser()与自定义声明一起传递给 方法。所以
JWT::fromUser($user,['role' => $user->role])
回答by Francesco Malatesta
It's strange, specifying some $customClaimsas second parameter for the attempt()method actually works for me.
奇怪的是,将一些$customClaims指定为attempt()方法的第二个参数实际上对我有用。
However, have you tried to use the JWTFactoryFacade? It lets you create every kind of token you want.
但是,您是否尝试过使用JWTFactoryFacade?它可以让你创建你想要的各种令牌。
You can get more info here: JWT-Auth Creating Tokens Page.
您可以在此处获取更多信息:JWT-Auth 创建令牌页面。
As the installation guide suggests, don't forget to add it as a Facade while installing JWT-Auth!
正如安装指南所建议的,在安装 JWT-Auth 时不要忘记将其添加为 Facade!
Hope it helps!
希望能帮助到你!
回答by Lithium
It seems that there isn't a cleaner way in the current stable version of JWTAuth[0.5.9].
在当前稳定版本的 JWTAuth[0.5.9] 中似乎没有更简洁的方法。
Take a look on the following issues #89#108
As the author pointed out in his comments there will be improvements in his next release covering this issue. You can take a look on his develop branch.
正如作者在评论中指出的那样,他的下一个版本将对此问题进行改进。你可以看看他的开发分支。
回答by Cyber
JWT v1.0's documentation causes confusion.
Add this method to your user model, so you can add custom claims when you authenticate users:
JWT v1.0的文档引起混乱。
将此方法添加到您的用户模型中,以便您可以在对用户进行身份验证时添加自定义声明:
public function getJWTCustomClaims()
{
return = [
'type' => 'driver',
'id' => $this->driver->id
];
}

