BASH 在寻找匹配的 ``' 时出现意外的 EOF
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BASH unexpected EOF while looking for matching ``'
提问by Nathan30
I have a BASH project for university and I have two errors that I don't understand
我有一个大学的 BASH 项目，我有两个我不明白的错误
here is my script BASH :
这是我的脚本 BASH ：
#!/bin/bash
proc_name=`cat /proc/cpuinfo | grep 'model name' | cut -d':' -f2 |cut -d'@' -f1 | uniq`;
proc_freq=`cat /proc/cpuinfo | grep 'model name' | cut -d':' -f2 |cut -d'@' -f2 | uniq`;
proc_core=`cat /proc/cpuinfo | grep 'cpu cores' | cut -d':' -f2 | uniq`;
proc_hyperthreading=`cat /proc/cpuinfo | grep 'siblings' | cut -d':' -f2 | uniq`;
proc_architecture=`lscpu | grep '64-bit' | cut -d',' -f2 | cut -d'-' -f1`;
proc_cache_L1=`lscpu | grep 'Cache L1i' | cut -d':' -f2 | sed "s/\ \ */\ /g"`;
proc_cache_L2=`lscpu | grep 'Cache L2' | cut -d':' -f2 | sed "s/\ \ */\ /g"`;
proc_cache_L3=`lscpu | grep 'Cache L3' | cut -d':' -f2 | sed "s/\ \ */\ /g"`;
proc_virtualisation=`lscpu | grep 'Virtualisation' | cut -d':' -f2 |sed "s/\ \ */\ /g"`;
proc_load_average=`w | head -1 | cut -d" " -f12 | cut -d"," -f1-2` | tr ',' '.'`
ip_infos_addr_ipv4=`/sbin/ifconfig eth0 | awk '/inet adr:/{print }' | awk -F ':' '{print }'`;
ip_infos_addr_ipv6=`/sbin/ifconfig eth0 | awk '/adr inet6:/{print }'`;
ip_publique_addr=`dig +short myip.opendns.com @resolver1.opendns.com`;
carte_reseau=`lspci |grep Ethernet | cut -d":" -f3`;
echo -e "$proc_name\n$proc_freq\n$proc_core\n$proc_hyperthreading\n$proc_architecture\n$proc_cache_L1\n$proc_cache_L2\n$proc_cache_L3\n$proc_virtualisation\n$proc_load_average\n$ip_infos_addr_ipv4\n$ip_infos_addr_ipv6\n$ip_publique_addr\n$carte_reseau" > Collecteur/collecteur_cpu_reseau.txt;
And here is the two errors I have :
这是我的两个错误：
./collecteur_cpu_reseau: line 17: unexpected EOF while looking for matching ``'
./collecteur_cpu_reseau: line 21: syntax error: unexpected end of file
Thanks in advance for your help
在此先感谢您的帮助
回答by Charles Duffy
proc_load_average=`w | head -1 | cut -d" " -f12 | cut -d"," -f1-2` | tr ',' '.'`
...needs to be...
...需要是...
# remove the extra backtick
proc_load_average=`w | head -1 | cut -d" " -f12 | cut -d"," -f1-2 | tr ',' '.'`
...or better...
...或更好...
# use parens, not backticks
proc_load_average=$(w | head -1 | cut -d" " -f12 | cut -d"," -f1-2 | tr ',' '.')
...or better...
...或更好...
# read the content straight from procfs without the big silly pipeline
read -r loadavg_1min loadavg_5min loadavg_10min _ </proc/loadavg
echo "1-minute load average: $loadavg_1min"
That said, this script as a whole is unsalvageably awful.
也就是说，这个剧本作为一个整体是无可挽回的糟糕。
For instance, consider the following alternative to all the messing around in /proc/cpuinfo:
例如，考虑以下替代 in 的所有乱七八糟的方法/proc/cpuinfo：
declare -A cpuinfo=( ) # create an associative array
# read line-by-line; see http://mywiki.wooledge.org/BashFAQ/001
while IFS=$'\t:' read -r k v || [[ $k ]]; do
[[ $v ]] || continue
cpuinfo[$k]=${v# } # trim leading space; see http://wiki.bash-hackers.org/syntax/pe
done </proc/cpuinfo
echo "Model name: ${cpuinfo['model name']%@*}"
echo "Model freq: ${cpuinfo['model name']#*@}"
echo "Actual frequency: ${cpuinfo['cpu MHz']}"
echo "Siblings: ${cpuinfo['siblings']}"
...isn't that easier? You can deploy the same strategy reading the output of a command like lscpuby substituting < <(lscpu)for </proc/cpuinfo.
……那不是更容易吗？您可以像部署同样的策略读取命令的输出lscpu通过替换< <(lscpu)的</proc/cpuinfo。
