Python - 将数组中的字符串转换为日期
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Python - converting strings in an array to dates
提问by kaksat
I have read an array of strings from a TXT file and saved it as an array (of over thousand values) using such a line:
我已经从 TXT 文件中读取了一个字符串数组，并使用这样一行将其保存为一个数组（超过一千个值）：
dates = np.genfromtxt('filename.txt', delimiter=";", usecols=(0), dtype=None)
Next, I would like to convert strings into dates. I tried to use the line:
接下来，我想将字符串转换为日期。我尝试使用该行：
dates2 = dt.datetime.strptime([dates], '"%Y-%m-%d"').date()
however, I got an error:
但是，我收到了一个错误：
TypeError: must be string, not list
类型错误：必须是字符串，而不是列表
I figured out that such a code works fine:
我发现这样的代码工作正常：
data1='"2010-02-28"'
data1_1 = dt.datetime.strptime(data1, '"%Y-%m-%d"').date()
How should I deal with the described problem?
我应该如何处理所描述的问题？
采纳答案by DeepSpace
Note to future readers:Please do not edit this answer. '"%Y-%m-%d"'is not a mistake. OP's dates are surrounded by quotes.
给未来读者的注意事项：请不要编辑此答案。'"%Y-%m-%d"'不是错误。OP 的日期用引号括起来。
datesis a list of strings. So if you want to create a list of dates from its elements:
dates是一个字符串列表。因此，如果您想从其元素创建日期列表：
dates_list = [dt.datetime.strptime(date, '"%Y-%m-%d"').date() for date in dates]
This line iterates over the strings in the dateslist and using list comprehension to create a new list of dates.
此行迭代dates列表中的字符串并使用列表理解来创建新的日期列表。
回答by NaabNuts
you can use split for faster result:
您可以使用 split 以获得更快的结果：
from datetime import datetime
today = datetime.now().strftime("%Y-%m-%d").split('-')
Hope I helped!
希望我有所帮助！
