asp.net-mvc 如何通过 Url.Action 传递模型？
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how to pass Model with Url.Action?
提问by user584018
I want to return a partial view in Jquery Dailog and wanted to pass the viewmodel object to particular controller action, how to do that?
我想在 Jquery Dailog 中返回一个局部视图，并想将 viewmodel 对象传递给特定的控制器操作，该怎么做？
View
看法
@Html.DropDownListFor(model => model.SelectedCountry, new SelectList(Model.CountryList, "CountryCode", "CountryName"), "---SELECT COUNTRY---",
new { @class = "chosen", @onchange = "this.form.action='/Home/Index'; this.form.submit(); " })
<input type="button" id="button1" value="Push"/>
<div id="dialog" title="Report" style="overflow: hidden;"></div>
Js
JS
<script type="text/javascript">
$(function () {
$('#dialog').dialog({
autoOpen: false,
width: 400,
resizable: false,
title: 'Report',
modal: true,
open: function() {
//here how to pass viewmodel
$(this).load("@Url.Action("CreatePartial")");
},
buttons: {
"Close": function () {
$(this).dialog("close");
}
}
});
$('#button1').click(function () {
$('#dialog').dialog('open');
});
});
Controller
控制器
public ActionResult CreatePartial(HomeViewModel homeViewModel)
{
return PartialView("_CreatePartial", homeViewModel);
}
Currently, "homeViewModel.SelectedCountry" is Null, how to pass model in Jquery?
当前，"homeViewModel.SelectedCountry" 为 Null，如何在 Jquery 中传递模型？
采纳答案by developer10214
You convert the model into an JSON object by using the the build-in JSON-helper, just modify your request to:
您可以使用内置的 JSON-helper 将模型转换为 JSON 对象，只需将您的请求修改为：
$(this).load('@Url.Action("CreatePartial")',@Html.Raw(Json.Encode(Model)));
@Html.Raw is needed to prevent HTML-Encoding.
需要@Html.Raw 来防止 HTML 编码。
I tested it and it worked.
我测试了它并且它起作用了。
回答by Serg Rogovtsev
If you're using AJAX, you should not use HTTP GET to pass model to server. Instead use HTTP POST (as in $().ajax({method: 'POST'})and pass data as POST data ($().ajax({method: 'POST', data: @Html.Raw(Json.Encode(Model))}))
如果您使用 AJAX，则不应使用 HTTP GET 将模型传递给服务器。而是使用 HTTP POST（如 in$().ajax({method: 'POST'})并将数据作为 POST 数据 ( $().ajax({method: 'POST', data: @Html.Raw(Json.Encode(Model))}))
