在移动版android中打开google play商店的链接
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open link of google play store in mobile version android
提问by ghostrider
I have link of my other apps in my latest app, and I open them in that way.
我在最新的应用程序中有其他应用程序的链接，我以这种方式打开它们。
Uri uri = Uri.parse("url");
Intent intent = new Intent (Intent.ACTION_VIEW, uri);
startActivity(intent);
this codes opens the browser version of google play store.
此代码打开谷歌播放商店的浏览器版本。
When trying to open from my phone, the phone prompts if I want to use a browser or google play and if I choose the second one it opens the mobile version of google play store.
尝试从手机打开时，手机会提示我是要使用浏览器还是 google play，如果我选择第二个，它会打开 google play 商店的移动版本。
Can you tell me how can this happen at once? I mean not ask me but directly open the mobile version of google play, the one that I see while open it directly from phone.
你能告诉我这怎么会一下子发生？我的意思是不要问我，而是直接打开手机版的google play，我在手机上直接打开时看到的那个。
回答by Eric
You'll want to use the specified marketprotocol:
您将要使用指定的market协议：
final String appPackageName = "com.example"; // Can also use getPackageName(), as below
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=" + appPackageName)));
Keep in mind, this will crash on any device that does not have the Market installed (the emulator, for example). Hence, I would suggest something like:
请记住，这将在任何未安装 Market 的设备（例如模拟器）上崩溃。因此，我建议如下：
final String appPackageName = getPackageName(); // getPackageName() from Context or Activity object
try {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=" + appPackageName)));
} catch (android.content.ActivityNotFoundException anfe) {
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("http://play.google.com/store/apps/details?id=" + appPackageName)));
}
While using getPackageName()from Contextor subclass thereof for consistency (thanks @cprcrack!). You can find more on Market Intents here: link.
在使用getPackageName()fromContext或其子类以保持一致性时（感谢@cprcrack！）。您可以在此处找到有关市场意图的更多信息：链接。
回答by Chirag Ghori
Below code may helps you for display application link of google play sore in mobile version.
下面的代码可以帮助您在移动版本中显示 google play sore 的应用程序链接。
For Application link :
申请链接：
Uri uri = Uri.parse("market://details?id=" + mContext.getPackageName());
Intent myAppLinkToMarket = new Intent(Intent.ACTION_VIEW, uri);
try {
startActivity(myAppLinkToMarket);
} catch (ActivityNotFoundException e) {
//the device hasn't installed Google Play
Toast.makeText(Setting.this, "You don't have Google Play installed", Toast.LENGTH_LONG).show();
}
For Developer link :
对于开发人员链接：
Uri uri = Uri.parse("market://search?q=pub:" + YourDeveloperName);
Intent myAppLinkToMarket = new Intent(Intent.ACTION_VIEW, uri);
try {
startActivity(myAppLinkToMarket);
} catch (ActivityNotFoundException e) {
//the device hasn't installed Google Play
Toast.makeText(Settings.this, "You don't have Google Play installed", Toast.LENGTH_LONG).show();
}
回答by Dmitriy Tarasov
You can use Android Intentslibrary for opening your application page at Google Play like that:
您可以使用Android Intents库在 Google Play 中打开您的应用程序页面，如下所示：
Intent intent = IntentUtils.openPlayStore(getApplicationContext());
startActivity(intent);
回答by Denis Gladkiy
回答by Paolo Rovelli
You can check if the Google Play Storeapp is installed and, if this is the case, you can use the "market://"protocol.
您可以检查是否安装了Google Play Store应用程序，如果是这种情况，您可以使用“market://”协议。
final String my_package_name = "........." // <- HERE YOUR PACKAGE NAME!!
String url = "";
try {
//Check whether Google Play store is installed or not:
this.getPackageManager().getPackageInfo("com.android.vending", 0);
url = "market://details?id=" + my_package_name;
} catch ( final Exception e ) {
url = "https://play.google.com/store/apps/details?id=" + my_package_name;
}
//Open the app page in Google Play store:
final Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_CLEAR_WHEN_TASK_RESET);
startActivity(intent);
回答by Paolo Rovelli
Open app page on Google Play:
在 Google Play 上打开应用页面：
Intent intent = new Intent(Intent.ACTION_VIEW,
Uri.parse("market://details?id=" + context.getPackageName()));
startActivity(intent);
