PHP：调用另一个类的方法
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PHP: Calling another class' method
提问by Ryan
I'm still learning OOP so this might not even be possible (although I would be surprised if so), I need some help calling another classes method.
我仍在学习 OOP，所以这甚至可能不可能（尽管如果是这样我会感到惊讶），我需要一些帮助来调用另一个类方法。
For example in ClassA Ihave this method:
例如在ClassA I有这个方法：
function getName()
{
return $this->name;
}
now from ClassB(different file, but in the same directory), I want to call ClassA's getName(), how do I do that? I tried to just do an include()but that does not work.
现在从ClassB（不同的文件，但在同一目录中），我想调用ClassA's getName()，我该怎么做？我试图只做一个，include()但这不起作用。
Thanks!
谢谢！
回答by codingbiz
//file1.php
<?php
class ClassA
{
private $name = 'John';
function getName()
{
return $this->name;
}
}
?>
//file2.php
<?php
include ("file1.php");
class ClassB
{
function __construct()
{
}
function callA()
{
$classA = new ClassA();
$name = $classA->getName();
echo $name; //Prints John
}
}
$classb = new ClassB();
$classb->callA();
?>
回答by PeeHaa
If they are separate classes you can do something like the following:
如果它们是单独的类，您可以执行以下操作：
class A
{
private $name;
public function __construct()
{
$this->name = 'Some Name';
}
public function getName()
{
return $this->name;
}
}
class B
{
private $a;
public function __construct(A $a)
{
$this->a = $a;
}
function getNameOfA()
{
return $this->a->getName();
}
}
$a = new A();
$b = new B($a);
$b->getNameOfA();
What I have done in this example is first create a new instance of the Aclass. And after that I have created a new instance of the Bclass to which I pass the instance of Ainto the constructor. Now Bcan access all the public members of the Aclass using $this->a.
我在这个例子中所做的是首先创建一个A类的新实例。之后，我创建了一个B类的新实例，我将 的实例传递A给构造函数。现在B可以访问的所有公共成员A使用类$this->a。
Also note that I don't instantiate the Aclass inside the Bclass because that would mean I tighly couple the two classes. This makes it hard to:
另请注意，我不会在A类中实例化B类，因为这意味着我将两个类紧密耦合。这使得很难：
- unit test your
Bclass - swap out the
Aclass for another class
- 单元测试你的
B课程 - 将
A班级换成另一个班级
回答by Rawkode
You would need to have an instance of ClassA within ClassB or have ClassB inherit ClassA
您需要在 ClassB 中拥有 ClassA 的实例或让 ClassB 继承 ClassA
class ClassA {
public function getName() {
echo $this->name;
}
}
class ClassB extends ClassA {
public function getName() {
parent::getName();
}
}
Without inheritance or an instance method, you'd need ClassA to have a static method
没有继承或实例方法，你需要 ClassA 有一个静态方法
class ClassA {
public static function getName() {
echo "Rawkode";
}
}
--- other file ---
--- 其他文件 ---
echo ClassA::getName();
echo ClassA::getName();
If you're just looking to call the method from an instance of the class:
如果您只是想从类的实例中调用该方法：
class ClassA {
public function getName() {
echo "Rawkode";
}
}
--- other file ---
--- 其他文件 ---
$a = new ClassA();
echo $a->getName();
Regardless of the solution you choose, require 'ClassA.phpis needed.
无论您选择哪种解决方案，require 'ClassA.php都是需要的。
回答by martin-lundberg
File 1
文件 1
class ClassA {
public $name = 'A';
public function getName(){
return $this->name;
}
}
File 2
档案 2
include("file1.php");
class ClassB {
public $name = 'B';
public function getName(){
return $this->name;
}
public function callA(){
$a = new ClassA();
return $a->getName();
}
public static function callAStatic(){
$a = new ClassA();
return $a->getName();
}
}
$b = new ClassB();
echo $b->callA();
echo $b->getName();
echo ClassB::callAStatic();
