scala 调用超级构造函数
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Call Super Constructor
提问by Echo
I have a custom exception class like the following :
我有一个自定义异常类，如下所示：
case class CustomException(errorMsg:String) extends Exception(error:String)
All what I need that when I catch exception is to throw my custom exception and pass my error message to the custom exception . I expect from CustomException constructor to call super(errMsg) However , this isn't what goes now and I got a compilation error .
当我捕获异常时，我所需要的只是抛出我的自定义异常并将我的错误消息传递给自定义异常。我希望从 CustomException 构造函数调用 super(errMsg) 但是，这不是现在发生的事情，我收到了编译错误。
catch {
case s: Exception => throw CustomException("This is a custom message")
}
How could I call the super constructor :
我怎么能调用超级构造函数：
super(errorMessage)
回答by Kim Stebel
case class CustomException(errorMsg:String) extends Exception(errorMsg)
回答by dhg
case class CustomException(errorMsg:String) extends Exception(errorMsg)
You're calling the superclass's constructor, but the argument you are passing (error) isn't bound to anything.
您正在调用超类的构造函数，但您传递的参数 ( error) 未绑定到任何内容。
