javascript 将对象转换或包装成数组以获取复杂的 JSON
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javascript convert or wrap object into array for complex JSON
提问by Kevin
I have a JSON that looks something like this:
我有一个看起来像这样的 JSON：
var countries = [
{
name: 'united states',
program: {
name: 'usprogram'
}
},
{
name: 'mexico',
program: {
name: 'mexico program'
}
},
{
name: 'panama',
program: [
{
name: 'panama program1'
},
{
name: 'panama program2'
}
]
},
{
name: 'canada'
}
];
Is there a way to ALWAYS wrap the countries.programsobject into an array such that the final output looks something like this? I tried some of the utility functions in underscoreJS, but the solution has eluded me.
有没有办法始终将countries.programs对象包装到一个数组中，以便最终输出看起来像这样？我在 underscoreJS 中尝试了一些实用程序函数，但我没有找到解决方案。
var countries = [
{
name: 'united states',
program: [ //need to wrap this object into an array
{
name: 'usprogram'
}
]
},
{
name: 'mexico',
program: [ //need to wrap this object into an array
{
name: 'mexico program'
}
]
},
{
name: 'panama',
program: [
{
name: 'panama program1'
},
{
name: 'panama program2'
}
]
},
{
name: 'canada'
}
];
Thanks!
谢谢！
回答by Amadan
Not automatic, no. Loop through the countries, then country.program = [].concat(country.program). This last piece of magic will wrap the value if it is not an array, and leave it as-is if it is. Mostly. (It will be a different, but equivalent array).
不是自动的，没有。循环遍历国家，然后country.program = [].concat(country.program)。如果它不是数组，最后一个魔术将包装该值，如果它是，则保持原样。大多。（这将是一个不同但等效的数组）。
EDIT per request:
每个请求编辑：
_.each(countries, function(country) {
country.program = [].concat(country.program);
});
回答by alex
Something like this could work
像这样的东西可以工作
_.each(countries, function(country) {
! _.isArray(country.program) && (country.program = [country.program]);
});
