java 从Android上传图片到PHP服务器
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Upload a picture from Android to PHP server
提问by SilentCoder
I am trying to upload file to a php server from my android device. There is thread with same question but he is using a different method. My Android side code works fine and shows no error message but server is not receiving any file. here is my sample code, I found it online.
我正在尝试从我的 android 设备将文件上传到 php 服务器。有一个线程有同样的问题，但他使用的是不同的方法。我的 Android 端代码工作正常，没有显示错误消息，但服务器没有收到任何文件。这是我的示例代码，我在网上找到的。
import java.io.FileInputStream;
import android.app.Activity;
import android.os.Bundle;
import java.io.DataInputStream;
import java.io.DataOutputStream;
import java.io.File;
import java.io.IOException;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import android.util.Log;
public class uploadfile extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
doFileUpload();
}
private void doFileUpload(){
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String exsistingFileName = "/sdcard/def.jpg";
// Is this the place are you doing something wrong.
String lineEnd = "rn";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "http://192.168.1.6/index.php";
try
{
//------------------ CLIENT REQUEST
Log.e("MediaPlayer","Inside second Method");
FileInputStream fileInputStream = new FileInputStream(new File(exsistingFileName) );
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\""
+ exsistingFileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
Log.e("MediaPlayer","Headers are written");
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0){
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.e("MediaPlayer","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("MediaPlayer", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("MediaPlayer","Server Response"+str);
}
inStream.close();
}
catch (IOException ioex){
Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex);
}
}
}
and my php server side code is as follows
我的php服务器端代码如下
<?php
$target_path = "uploads/";
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['uploadedfile']['name']).
" has been uploaded";
}
else{
echo "There was an error uploading the file, please try again!";
}
?>
Apache is running. When i run server, this error msg appears There was an error uploading the file, please try again!. I have checked the log data in eclipse and what i think is the socket problem but i am not sure. Please help if anyone knows the solution.
阿帕奇正在运行。当我运行服务器时，出现此错误消息上传文件时出错，请重试！。我已经检查了 eclipse 中的日志数据，我认为是套接字问题，但我不确定。如果有人知道解决方案，请帮助。
11-28 05:37:55.310: DEBUG/SntpClient(59): request time failed: java.net.SocketException: Address family not supported by protocol
回答by George Violaris
It seems that the server is not responding to the client. Try uploading using an ftp connection through the Android application, if that works then check your Apache configuration on accepting connections and the writable directories. When I had a similar problem it turned out that my directory gave no write privileges.
服务器似乎没有响应客户端。尝试通过 Android 应用程序使用 ftp 连接上传，如果可行，请检查您的 Apache 配置是否接受连接和可写目录。当我遇到类似问题时，结果证明我的目录没有写权限。
Is the error from Java or from Apache?
错误是来自 Java 还是来自 Apache？
回答by sp3tsnaz
Change your code in the following way for the correct escape sequences:
按以下方式更改代码以获得正确的转义序列：
Replace
代替
String lineEnd = "rn";
with
和
String lineEnd = "\r\n";
