java 如何禁用 AlertDialog 内的按钮？
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How do you disable a button inside of an AlertDialog?
提问by Frank Bozzo
I am trying to write an AlertDialogwith 3 buttons. I want the middle, Neutral Button to be disabled if a certain condition is not met.
我正在尝试AlertDialog用 3 个按钮编写一个。如果不满足某个条件，我希望中间的 Neutral Button 被禁用。
Code
代码
int playerint = settings.getPlayerInt();
int monsterint = settings.getMonsterInt();
AlertDialog.Builder alertbox = new AlertDialog.Builder(this);
alertbox.setMessage("You have Encountered a Monster");
alertbox.setPositiveButton("Fight!",
new DialogInterface.OnClickListener() {
// do something when the button is clicked
public void onClick(DialogInterface arg0, int arg1) {
createMonster();
fight();
}
});
alertbox.setNeutralButton("Try to Outwit",
new DialogInterface.OnClickListener() {
// do something when the button is clicked
public void onClick(DialogInterface arg0, int arg1) {
// This should not be static
// createTrivia();
trivia();
}
});
// Return to Last Saved CheckPoint
alertbox.setNegativeButton("Run Away!",
new DialogInterface.OnClickListener() {
// do something when the button is clicked
public void onClick(DialogInterface arg0, int arg1) {
runAway();
}
});
// show the alert box
alertbox.show();
// Intellect Check
Button button = ((AlertDialog) alertbox).getButton(AlertDialog.BUTTON_NEUTRAL);
if(monsterint > playerint) {
button.setEnabled(false);
}
}
The line:
线路：
Button button = ((AlertDialog) alertbox).getButton(AlertDialog.BUTTON_NEUTRAL);
Gives error:
给出错误：
Cannot cast from AlertDialog.Builder to AlertDialog
无法从 AlertDialog.Builder 转换为 AlertDialog
How do I fix this?
我该如何解决？
回答by Devunwired
You can't call getButton()on the AlertDialog.Builder. It has to be called on the resulting AlertDialogafter creation. In other words
你不能打电话getButton()的AlertDialog.Builder。必须AlertDialog在创建后的结果上调用它。换句话说
AlertDialog.Builder alertbox = new AlertDialog.Builder(this);
//...All your code to set up the buttons initially
AlertDialog dialog = alertbox.create();
Button button = dialog.getButton(AlertDialog.BUTTON_NEUTRAL);
if(monsterint > playerint) {
button.setEnabled(false);
}
The builder is just a class to make constructing the dialog easier...it isn't the actual dialog itself.
构建器只是一个使构建对话框更容易的类……它不是实际的对话框本身。
HTH
HTH
回答by Michal
Better solution in my opinion:
我认为更好的解决方案：
AlertDialog.Builder builder = new AlertDialog.Builder(context);
builder.setPositiveButton("Positive", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
// some code
}
});
AlertDialog alertDialog = builder.create();
alertDialog.setOnShowListener(new DialogInterface.OnShowListener() {
@Override
public void onShow(DialogInterface dialog) {
if(**some condition**)
{
Button button = alertDialog.getButton(AlertDialog.BUTTON_POSITIVE);
if (button != null) {
button.setEnabled(false);
}
}
}
});
回答by Ashraf Sousa
The trick is that you need to use the AlertDialogobject retuned by AlertDialog.Builder.show()method. No need to call AlertDialog.Builder.create().
诀窍是您需要使用AlertDialog通过AlertDialog.Builder.show()方法重新调整的对象。不需要打电话AlertDialog.Builder.create()。
Example:
例子：
AlertDialog dialog = alertbox.show();
if(monsterint > playerint) {
Button button = dialog.getButton(AlertDialog.BUTTON_NEUTRAL);
button.setEnabled(false);
}
