objective-c 将秒整数转换为 HH:MM, iPhone

Convert Seconds Integer To HH:MM, iPhone

提问by Stumf

I am struggling with this. I have a value in seconds that I want to display in a label in HH:MM format. I have searched the internet for ages and found some answers, but either not fully understood them, or they seem like an odd way of doing what I want. If someone could help me out on this one that would be great! Bear in mind that I am new to this games so this question may seem like a really basic one to the more experienced out there.

我正在为此而苦苦挣扎。我有一个以秒为单位的值，我想以 HH:MM 格式显示在标签中。我已经在互联网上搜索了很长时间并找到了一些答案，但要么没有完全理解它们，要么它们看起来像是做我想做的事情的奇怪方式。如果有人能帮我解决这个问题，那就太好了！请记住，我是这个游戏的新手，所以这个问题对于更有经验的人来说似乎是一个非常基本的问题。

回答by Rohit Agarwal

I was looking for the same thing that you are looking but couldn't find one. So I wrote one -

我正在寻找与您正在寻找的相同的东西，但找不到。于是我写了一篇——

- (NSString *)timeFormatted:(int)totalSeconds
{

    int seconds = totalSeconds % 60; 
    int minutes = (totalSeconds / 60) % 60; 
    int hours = totalSeconds / 3600; 

    return [NSString stringWithFormat:@"%02d:%02d:%02d",hours, minutes, seconds]; 
}

works perfectly in Swiftas well:

在Swift中也能完美运行：

 func timeFormatted(totalSeconds: Int) -> String {
    let seconds: Int = totalSeconds % 60
    let minutes: Int = (totalSeconds / 60) % 60
    let hours: Int = totalSeconds / 3600
    return String(format: "%02d:%02d:%02d", hours, minutes, seconds)
 }

回答by edukulele

In iOS 8.0 and higher versions it can also be done with NSDateComponentsFormatter. I need to mention that it will format the string without first leading zero, for example '9:30', but not '09:30'. But if you like to use formatters, you can use this code:

在 iOS 8.0 及更高版本中，也可以使用NSDateComponentsFormatter. 我需要提到的是，它会格式化字符串，而没有第一个前导零，例如 '9:30'，但不是 '09:30'。但如果你喜欢使用格式化程序，你可以使用以下代码：

-(NSString *)getTimeStringFromSeconds:(double)seconds
{
     NSDateComponentsFormatter *dcFormatter = [[NSDateComponentsFormatter alloc] init];
     dcFormatter.zeroFormattingBehavior = NSDateComponentsFormatterZeroFormattingBehaviorPad;
     dcFormatter.allowedUnits = NSCalendarUnitHour | NSCalendarUnitMinute;
     dcFormatter.unitsStyle = NSDateComponentsFormatterUnitsStylePositional;
     return [dcFormatter stringFromTimeInterval:seconds];
}

回答by Mongi Zaidi

This is how I do it:

这就是我的做法：

-(NSString *)formatTimeFromSeconds:(int)numberOfSeconds
{

    int seconds = numberOfSeconds % 60;
    int minutes = (numberOfSeconds / 60) % 60;
    int hours = numberOfSeconds / 3600;

    //we have >=1 hour => example : 3h:25m
    if (hours) {
        return [NSString stringWithFormat:@"%dh:%02dm", hours, minutes];
    }
    //we have 0 hours and >=1 minutes => example : 3m:25s
    if (minutes) {
        return [NSString stringWithFormat:@"%dm:%02ds", minutes, seconds];
    }
    //we have only seconds example : 25s
    return [NSString stringWithFormat:@"%ds", seconds];
}

回答by Aks

For Swift:

对于斯威夫特：

func formatTimeInSec(totalSeconds: Int) -> String {
    let seconds = totalSeconds % 60
    let minutes = (totalSeconds / 60) % 60
    let hours = totalSeconds / 3600
    let strHours = hours > 9 ? String(hours) : "0" + String(hours)
    let strMinutes = minutes > 9 ? String(minutes) : "0" + String(minutes)
    let strSeconds = seconds > 9 ? String(seconds) : "0" + String(seconds)

    if hours > 0 {
        return "\(strHours):\(strMinutes):\(strSeconds)"
    }
    else {
        return "\(strMinutes):\(strSeconds)"
    }
}

回答by Isuru

While @Aks' answerfor Swift works, I'm a little skeptic about hardcoding values in my code. @edukulele's answeris much more cleaner but it's in Objective-C. I translated it to Swift with a slight change. I normally write my formatters as lazy vars.

虽然@Aks对 Swift的回答有效，但我对代码中的硬编码值有点怀疑。@edukulele 的答案更简洁，但它在 Objective-C 中。我将它翻译成 Swift，稍作改动。我通常将格式化程序写为lazy vars。

private lazy var dateFormatter: NSDateComponentsFormatter = {
    let formatter = NSDateComponentsFormatter()
    formatter.zeroFormattingBehavior = .Pad
    formatter.allowedUnits = [.Hour, .Minute, .Second]
    formatter.unitsStyle = .Positional
    return formatter
}()

回答by Perry C

For Swift with clock count

对于带有时钟计数的 Swift

    var timer = NSTimer()
    var count = 1
    func updateTime() {
        count++
        let seconds = count % 60
        let minutes = (count / 60) % 60
        let hours = count / 3600
        let strHours = hours > 9 ? String(hours) : "0" + String(hours)
        let strMinutes = minutes > 9 ? String(minutes) : "0" + String(minutes)
        let strSeconds = seconds > 9 ? String(seconds) : "0" + String(seconds)

        if hours > 0 {
            clockOutlet.text = "\(strHours):\(strMinutes):\(strSeconds)"
        }
        else {
            clockOutlet.text = "\(strMinutes):\(strSeconds)"
        }   
    }