javascript 用于检查 4 个不同字符组中是否至少存在 3 个的正则表达式
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Regex for checking that at least 3 of 4 different character groups exist
提问by Yonder
I'm trying to write a password validator.
我正在尝试编写一个密码验证器。
How can I see if my supplied string contains at least 3 different character groups?
如何查看我提供的字符串是否包含至少 3 个不同的字符组？
It's easy enough to check if they are existant or not ---but at least 3?
检查它们是否存在很容易——但至少有 3 个？
at least eight (8) characters
At least three different character groups
upper-case letter
lower-case letter
numeric
special characters !@#$%&/=?_.,:;-\
至少八 (8) 个字符
至少三个不同的字符组
大写字母
小写字母
数字
特殊字符 !@#$%&/=?_.,:;-\
(I'm using javascript for regex)
（我正在使用 javascript 进行正则表达式）
回答by Bart Kiers
Just to learn - would this kind of requirement be possible to implement in pure regex?
只是为了学习 - 这种要求可以在纯正则表达式中实现吗？
That'd make it a rather hard to read (and therefor maintain!) solution, but here it is:
这将使它成为一个相当难以阅读（并因此维护！）的解决方案，但它是：
(?mx)
^
(
(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9]) # must contain a-z, A-Z and 0-9
| # OR
(?=.*[a-z])(?=.*[A-Z])(?=.*[!@\#$%&/=?_.,:;\-]) # must contain a-z, A-Z and special
| # OR
(?=.*[a-z])(?=.*[0-9])(?=.*[!@\#$%&/=?_.,:;\-]) # must contain a-z, 0-9 and special
| # OR
(?=.*[A-Z])(?=.*[0-9])(?=.*[!@\#$%&/=?_.,:;\-]) # must contain A-Z, 0-9 and special
)
.{8,} # at least 8 chars
$
A (horrible) Javascript demo:
一个（可怕的）Javascript 演示：
var pw = "aa$aa1aa";
if(pw.match(/^((?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])|(?=.*[a-z])(?=.*[A-Z])(?=.*[!@#$%&\/=?_.,:;\-])|(?=.*[a-z])(?=.*[0-9])(?=.*[!@#$%&\/=?_.,:;\-])|(?=.*[A-Z])(?=.*[0-9])(?=.*[!@#$%&\/=?_.,:;\-])).{8,}$/)) {
print('Okay!');
} else {
print('Fail...');
}
prints: Okay!, as you can see on Ideone.
回答by Brad Christie
May as well join in on the fun:
不妨一起来凑热闹：
String.prototype.isValidPW = function(){
// First, check for at least 8 characters
if (this.length < 8) return false;
// next, check that we have at least 3 matches
var re = [/\d/, /[A-Z]/, /[a-z]/, /[!@#$%&\/=?_.,:;-]/], m = 0;
for (var r = 0; r < re.length; r++){
if ((this.match(re[r]) || []).length > 0) m++;
}
return m >= 3;
};
if ("P@ssW0rd".isValidPW()) alert('Acceptable!');
回答by Kshitij Saxena -KJ-
I am assuming that you will be using different regexes for different requirements. In that case, tell me if the following work for you:
我假设您将针对不同的要求使用不同的正则表达式。在这种情况下，请告诉我以下是否适合您：
var e = password.match(/.{8,}/); //At least 8 chars
var a = password.match(/[0-9]+/); //numeric
var b = password.match(/[A-Z]+/); //Capitals
var c = password.match(/[a-z]+/); //small letters
var d = password.match(/[!@#$%&/=?_.,:;-\]+/); //special chars
if (a + b + c + d > 2 && e) {// Success}
else {// Failure}
回答by gaRex
/**
* Function determine, wheter we have valid password
*
* @param {String} value
* @return {Boolean}
*/
function isValidPassword(value) {
// Here we define all our params
var validLength = 8,
minSuccess = 3,
isNumeric = + /\d+/.test(value),
isCapitals = + /[A-Z]+/.test(value),
isSmall = + /[a-z]+/.test(value),
isSpecial = + /[!@#$%&\/=\?_\.,:;\-]+/.test(value);
if (value.length < validLength) { // 8 symbols. We don`t need regexp here
return false;
}
if (isNumeric + isCapitals + isSmall + isSpecial < minSuccess) {
return false;
}
return true;
}
document.writeln(isValidPassword('abc'));
document.writeln(isValidPassword('abc123ABC'));
document.writeln(isValidPassword('abc123!23'));
回答by Bryce Siedschlaw
Crimson's answer didn't work for me. Here is what I have.
Crimson 的回答对我不起作用。这是我所拥有的。
var mystring = 'bLahbla\';
var valid_char_count = 0;
var lc = mystring.match(/[a-z]+/);
var uc = mystring.match(/[A-Z]+/);
var dc = mystring.match(/[0-9]+/);
var sc = mystring.match(/[\!\@\#$\%\&\=\?\_\.\,\:\;\-\]/);
if( lc ){ valid_char_count++; }
if( uc ){ valid_char_count++; }
if( dc ){ valid_char_count++; }
if( sc ){ valid_char_count++; }
if( valid_char_count >= 3 ){ /* success */ }
回答by herostwist
This will do all that in one regex
这将在一个正则表达式中完成所有这些
^.*(?=.{8,})(?=.*[a-z])(?=.*[A-Z])(?=.*[\d\W])(?=.*[!@#\$%&/=?_\.,:;-\\]).*$
^.*(?=.{8,})(?=.*[a-z])(?=.*[A-Z])(?=.*[\d\W])(?=.*[!@#\$%&/=?_\.,:;-\\]).*$
