java 我需要分隔一个整数然后在java中将数字相加
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I need to separate a integer then add the digits together in java
提问by Impact Pixel
Good morning, I am on now to lesson 4 and am having a bit of trouble using loops. Please note that I have seen it resolved using strings but I am trying to grasp loops.
早上好，我现在正在学习第 4 课，但在使用循环时遇到了一些麻烦。请注意，我已经看到它使用字符串解决，但我正在尝试掌握循环。
The reason for the trouble is I need to show both answers: The integer broken into individual number ex: 567 = 5 6 7
麻烦的原因是我需要显示两个答案：整数分解为单个数字例如：567 = 5 6 7
And then 567 = 18
然后 567 = 18
I am able to get the integer added together but am not sure on how to separate the integer first and then add the individual numbers together. I am thinking that I need to divide down to get to 0. For instance if its a 5 digit number /10000, /1000, /100, /10, /1
我能够将整数相加，但不确定如何先将整数分开，然后将各个数字相加。我想我需要除以得到 0。例如，如果它是一个 5 位数字 /10000、/1000、/100、/10、/1
But what if the user wants to do a 6 or 7 or even a 8 digit number?
但是如果用户想要输入 6 位或 7 位甚至 8 位数字呢？
Also I am assuming this would have to be first and then the addition of the individual integers would take place?
另外我假设这必须是第一次，然后会发生单个整数的相加？
thanks for the guidance:
感谢指导：
import java.util.Scanner;
public class spacing {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n;
System.out.print("Enter a your number: ");
n = in.nextInt();
int sum = 0;
while (n != 0) {
sum += n % 10;
n /= 10;
}
System.out.println("Sum: " + sum);
}
}
回答by Vivin Paliath
Since this is a lesson, I won't give you the solution outright, but I will give you some hints:
由于这是一个教训，我不会直接给你解决方案，但我会给你一些提示：
- You're only thinking in
int. Think inStringinstead. :) This will also take care of the case where users provide you numbers with a large number of digits. - You willneed to validate your input though; what if someone enters "12abc3"?
String.charAt(int)will be helpful.Integer.parseInt(String)will also be helpful.
- 你只是在想
int。String而是考虑一下。:) 这也将处理用户为您提供大量数字的情况。 - 您将需要验证您的输入，虽然; 如果有人输入“12abc3”怎么办？
String.charAt(int)会有所帮助。Integer.parseInt(String)也会有帮助。
You could also look at using longinstead of int; longhas an upper limit of 9,223,372,036,854,775,807 though.
你也可以看看 usinglong而不是int; long但上限为 9,223,372,036,854,775,807。
回答by Lajos Arpad
//I assume that the input is a string which contains only digits
public static int parseString(String input)
{
char[] charArray = input.toCharArray();
int sum = 0;
for (int index = 0; index < input.length; index++)
{
sum += Integer.parseInt(charArray[index] + "");
}
return sum;
}
Use the function above, pass your input to the function and use the output as you like.
使用上面的函数，将输入传递给函数并根据需要使用输出。
