ARC 不允许将 iOS 隐式转换为 NSNumber
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iOS Implicit conversion of int to NSNumber is disallowed with ARC
提问by Daniel
on following code i'm get the errormessage: Implicit conversion of 'int' to 'NSNumber *' is disallowed with ARC.
在以下代码中，我收到错误消息：ARC 不允许将“int”隐式转换为“NSNumber *”。
What i'm making wrong?
我做错了什么？
<pre>
<code>
NSDictionary *results = [jsonstring JSONValue];
NSNumber *success = [results objectForKey:@"success"]; // possible values for "success": 0 or 1
if (success == 1) { // ERROR implicit conversion of int to NSNumber disallowed with ARC
}
</code>
</pre>
Thanks for any help or hint!
感谢您的任何帮助或提示！
regards, Daniel
问候， 丹尼尔
回答by rishi
Erro because you are comparing NSNumberwith int.
错误，因为您正在NSNumber与int.
Try like -
尝试像 -
if ([success isEqual:[NSNumber numberWithInt:1]])
or
或者
if ([success intValue] == 1)
回答by rishi
You should use [success intValue] == 1. An NSNumber is a class, so number is a pointer, not the direct value.
你应该使用[success intValue] == 1. NSNumber 是一个类，所以 number 是一个指针，而不是直接值。
回答by omz
NSNumberis an object (i.e. a pointer), so you can't just compare it to a integer literal like 1. Instead you have to extract the intvalue from the number object:
NSNumber是一个对象（即指针），因此您不能将它与像1. 相反，您必须int从数字对象中提取值：
if ([success intValue] == 1) {
...
}
回答by tilo
If successshould indicate a boolean, you may want to try this
如果success应该指示一个布尔值，你可能想试试这个
NSDictionary *results = [jsonstring JSONValue];
NSNumber *success = [results objectForKey:@"success"];
if ([success boolValue]) {
// success!
}
