ios Swift Equatable 协议

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时间:2020-08-31 01:08:56  来源:igfitidea点击:

Swift Equatable Protocol

iosswiftxcode6

提问by Addison

I was folling this tutorial for Swift: https://www.raywenderlich.com/125311/make-game-like-candy-crush-spritekit-swift-part-1and came across this code:

我正在关注 Swift 的本教程:https: //www.raywenderlich.com/125311/make-game-like-candy-crush-spritekit-swift-part-1并遇到了以下代码:

func == (lhs: Cookie, rhs: Cookie) -> Bool {
    return lhs.column == rhs.column && lhs.row == rhs.row
}

I wrote exactly that, but Xcode is giving my these errors:

我正是这样写的,但 Xcode 给了我这些错误:

Consecutive declarations on a line must be separated by ';'
Expected declaration operators are only allowed at global scope

I found this code from apple's documentation: https://developer.apple.com/documentation/swift/equatable

我从苹果的文档中找到了这段代码:https: //developer.apple.com/documentation/swift/equatable

Which is very similar to what I wrote. Whats wrong? This seems like a bug to me. I am using Xcode 6 Beta 2

这与我写的非常相似。怎么了?这对我来说似乎是一个错误。我正在使用 Xcode 6 Beta 2

EDIT:

编辑:

This is my whole Cookie class:

这是我的整个 Cookie 课程:

class Cookie: Printable, Hashable {
    var column: Int
    var row: Int
    let cookieType: CookieType
    let sprite: SKSpriteNode?

    init(column: Int, row: Int, cookieType: CookieType) {
        self.column = column
        self.row = row
        self.cookieType = cookieType
    }

    var description: String {
        return "type:\(cookieType) square:(\(column),\(row))"
    }

    var hashValue: Int {
        return row * 10 + column
    }

    func ==(lhs: Cookie, rhs: Cookie) -> Bool {
        return lhs.column == rhs.column && lhs.row == rhs.row
    }
}

回答by Connor

Move this function

移动这个功能

func == (lhs: Cookie, rhs: Cookie) -> Bool {
    return lhs.column == rhs.column && lhs.row == rhs.row
}

Outside of the cookie class. It makes sense this way since it's overriding the == operator at the global scope when it is used on two Cookies.

在 cookie 类之外。这是有道理的,因为当它用于两个 Cookie 时,它​​会在全局范围内覆盖 == 运算符。

回答by Anish Parajuli ?

SWIFT 2:

快速 2:

As in swift 2 NSObjectalready conforms to Equatable.You don't need conformance at the top so it's like

正如在 swift 2 中NSObject已经符合Equatable.You 不需要在顶部符合所以它就像

class Cookie: NSObject {
    ...

}

And you need to override isEqualmethod as

并且您需要将isEqual方法覆盖为

class Cookie:NSObject{
    var column: Int
    var row: Int

    //..........

    override func isEqual(object: AnyObject?) -> Bool {
        guard let rhs = object as? Cookie else {
            return false
        }
        let lhs = self

        return lhs.column == rhs.column
    }

}

This time isEqualmethod is inside the class. :)

这个时间isEqual方法在类内部。:)

EDIT for SWIFT 3:Change this method as

编辑 SWIFT 3:将此方法更改为

override func isEqual(_ object: AnyObject?) -> Bool {
        guard let rhs = object as? Cookie else {
            return false
        }
        let lhs = self

        return lhs.column == rhs.column
    }

回答by Felipe Ignacio Noriega Alcaraz

making the class an NSObject solved the equatable problems for me...

使类成为 NSObject 为我解决了等价问题...

class Cookie: NSObject {
...
}

(got the tip from the iOS apprentice tutorials)

(从 iOS 学徒教程中得到提示)