java 比较两个字符串的“大于 '0' ..and NULL”
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Comparing two strings for "greater than '0' ..and NULL"
提问by richey
I am trying to dig my way through the strict Java methods and operators, but now, trying to 'translate' a piece of PHP code to Java (Android), I'm kinda stuck.
我试图通过严格的 Java 方法和运算符挖掘自己的方法，但是现在，试图将一段 PHP 代码“翻译”为 Java (Android)，我有点卡住了。
In PHP:
在 PHP 中：
if ($row['price']>'0'){
(.. do something if price is defined - and higher than zero ..)
}
The problem is that $row['price'] may be empty (in Java: null?) or contain '0' (zero). But how can I code that in Java in a smart and not too complicated way?
问题是 $row['price'] 可能为空（在 Java 中：null？）或包含 '0'（零）。但是我怎样才能以一种聪明而不是太复杂的方式在 Java 中编码呢？
回答by smichak
Assuming you got the price string in a variable price
假设您以可变价格获得价格字符串
String price = <get price somehow>;
try {
if (price != null && Integer.valueOf(price) > 0) {
do something with price...
}
} catch (NumberFormatException exception) {
}
回答by JahN EstaCado
you can use this:
你可以使用这个：
String price="somevalue";
int priceInt=Integer.valueOf(price);
try{
if( !price.equals("") && priceInt>0){
// if condition is true,do your thing here!
}
}catch (NullPointerException e){
//if price is null this part will be executed,in your case leave it blank
}
catch (NumberFormatException exception) {
}
