JavaScript：获取两个日期之间的所有月份？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/30464628/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
JavaScript: get all months between two dates?
提问by Richard
I have two date strings like this:
我有两个这样的日期字符串：
var startDate = '2012-04-01';
var endDate = '2014-11-01';
And I want to end up with an array of strings like this:
我想以这样的字符串数组结束：
var dates = ['2012-04-01', '2012-05-01', '2012-06-01' .... '2014-11-01',];
So far this is what I've got, but it's pretty ugly:
到目前为止，这是我所拥有的，但它非常丑陋：
var startDate = '2012-04-01';
var endDate = '2014-11-01';
var start = new Date(Date.parse(startDate));
var end = new Date(Date.parse(endDate))
var dates = [];
for (var i = start.getFullYear(); i < end.getFullYear() + 1; i++) {
dates.push(i + '-' + '-01');
}
console.log(dates);
Is there a better way? JSFiddle.
有没有更好的办法？JSFiddle。
回答by McCroskey
You can also use the excellent moment.js library:
您还可以使用优秀的 moment.js 库：
var startDate = moment('2012-04-01');
var endDate = moment('2014-11-01');
var result = [];
if (endDate.isBefore(startDate)) {
throw "End date must be greated than start date."
}
while (startDate.isBefore(endDate)) {
result.push(startDate.format("YYYY-MM-01"));
startDate.add(1, 'month');
}
回答by Rob M.
This should produce the desired output:
这应该会产生所需的输出：
function dateRange(startDate, endDate) {
var start = startDate.split('-');
var end = endDate.split('-');
var startYear = parseInt(start[0]);
var endYear = parseInt(end[0]);
var dates = [];
for(var i = startYear; i <= endYear; i++) {
var endMonth = i != endYear ? 11 : parseInt(end[1]) - 1;
var startMon = i === startYear ? parseInt(start[1])-1 : 0;
for(var j = startMon; j <= endMonth; j = j > 12 ? j % 12 || 11 : j+1) {
var month = j+1;
var displayMonth = month < 10 ? '0'+month : month;
dates.push([i, displayMonth, '01'].join('-'));
}
}
return dates;
}
Just call it with your existing date format:
只需使用您现有的日期格式调用它：
dateRange('2013-11-01', '2014-06-01')
// ["2013-11-01", "2013-12-01", "2014-01-01", "2014-02-01", "2014-03-01", "2014-04-01", "2014-05-01", "2014-06-01", "2014-07-01", "2014-08-01", "2014-09-01", "2014-10-01", "2014-11-01", "2014-12-01"]
回答by Michiel
If loading an extra library isn't a problem, you could always try the awesome MomentJS.
Gives for very clean and powerful date manipulation.
如果加载一个额外的库不是问题，你总是可以尝试很棒的 MomentJS。
提供非常干净和强大的日期操作。
var startDate = moment('2012-04-01');
var endDate = moment('2014-11-01');
var dates = [];
endDate.subtract(1, "month"); //Substract one month to exclude endDate itself
var month = moment(startDate); //clone the startDate
while( month < endDate ) {
month.add(1, "month");
dates.push(month.format('YYYY-MM-DD'));
}
console.log(dates);
JSFiddle here
JSFiddle在这里
回答by Matthieu Chavigny
const getMonths = (fromDate, toDate) => {
const fromYear = fromDate.getFullYear();
const fromMonth = fromDate.getMonth();
const toYear = toDate.getFullYear();
const toMonth = toDate.getMonth();
const months = [];
for(let year = fromYear; year <= toYear; year++) {
let month = year === fromYear ? fromMonth : 0;
const monthLimit = year === toYear ? toMonth : 11;
for(; month <= monthLimit; month++) {
months.push({ year, month })
}
}
return months;
}
const sample = getMonths(new Date('2022-07-28'), new Date('2023-03-20'));
console.log(sample);
document.write('check the console output');回答by bitifet
You are handling "logical" jumps, so you doesn't actually need timing arthmetics. So this is a simple counting problem:
您正在处理“逻辑”跳转，因此您实际上并不需要计时算法。所以这是一个简单的计数问题：
var startDate = '2012-04-01';
var endDate = '2014-11-01';
var dates = [];
var d0 = startDate.split('-');
var d1 = endDate.split('-');
for (
var y = d0[0];
y <= d1[0];
y++
) {
for (
var m = d0[1];
m <= 12;
m++
) {
dates.push(y+"-"+m+"-1");
if (y >= d1[0] && m >= d1[1]) break;
};
d0[1] = 1;
};
console.log(dates);
回答by golf4sp
All solutions above run in O(n^2) time complexity, which is not very efficient. See below solution in O(n) time complexity:
以上所有解决方案都以 O(n^2) 时间复杂度运行，这不是很有效。请参阅以下 O(n) 时间复杂度的解决方案：
function getAllMonths(start, end){
let startDate = new Date(start);
let startYear = startDate.getFullYear();
let startMonth = startDate.getMonth()+1;
let endDate = new Date(end);
let endYear = endDate.getFullYear();
let endMonth = endDate.getMonth()+1;
let countMonth = 0;
let countYear = 0;
let finalResult = [];
for(let a=startYear; a<=endYear; a++){
if(startYear<endYear){
if(countYear==0){
countMonth += 12-startMonth;
}else
if(countYear>0){
countMonth += 12;
}
countYear+=1;
startYear++;
}else
if(startYear==endYear){
countMonth+=endMonth;
}
}
for(let i=startMonth; i<=countMonth+startMonth; i++){
finalResult.push(startDate.getFullYear()+(Math.floor(i/12)) + "-" + Math.round(i%13) + "-" + "01");
}
return finalResult;
}
getAllMonths('2016-04-01', '2018-01-01');Might share a much more simpler code
可能会分享更简单的代码
回答by RR90
An example to get all first days of months between a given date and now using moment.js.
使用moment.js获取给定日期和现在之间所有月份的第一天的示例。
var getMonths = function (startDate) {
var dates = [];
for (var year = startDate.year(); year <= moment().year(); year++) {
var endMonth = year != moment().year() ? 11 : moment().month();
var startMonth = year === startDate.year() ? startDate.month() : 0;
for (var currentMonth = startMonth; currentMonth <= endMonth; currentMonth = currentMonth > 12 ? currentMonth % 12 || 11 : currentMonth + 1) {
var month = currentMonth + 1;
var displayMonth = month < 10 ? '0' + month : month;
dates.push([year, displayMonth, '01'].join('-'));
}
}
return dates;
};
回答by Robert Cunningham
Still not a very elegant answer, but arrives at the array of strings you want:
仍然不是一个非常优雅的答案，但会得到您想要的字符串数组：
var startDate = '2012-04-01';
var endDate = '2014-11-01';
var start = new Date(startDate);
var end = new Date(endDate);
var dates = [];
for (var i = start.getFullYear(); i < end.getFullYear() + 1; i++) {
for (var j = 1; j <= 12; j++) {
if (i === end.getFullYear() && j === end.getMonth() + 3) {
break;
}
else if (i === 2012 && j < 4){
continue;
}
else if (j < 10) {
var dateString = [i, '-', '0' + j, '-','01'].join('');
dates.push(dateString)
}
else {
var dateString = [i, '-', j, '-','01'].join('');
dates.push(dateString);
}
}
}
console.log(dates);
jsfiddle link here: http://jsfiddle.net/8kut035a/
jsfiddle 链接在这里：http: //jsfiddle.net/8kut035a/
