C# 如何将新的 DataRow 添加到 DataTable 中？
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How to add new DataRow into DataTable?
提问by malcoauri
I have a DataGridViewbinded to a DataTable(DataTablebinded to database). I need to add a DataRowto the DataTable. I'm trying to use the following code:
我有一个DataGridView绑定到DataTable（DataTable绑定到数据库）。我需要DataRow在DataTable. 我正在尝试使用以下代码：
dataGridViewPersons.BindingContext[table].EndCurrentEdit();
DataRow row = table.NewRow();
for (int i = 0; i < 28; i++)
{
row[i] = i.ToString();
}
But it doesn't work, DataGridViewhas never been added a new row. Please, tell me, how can I fix my code?
但它不起作用，DataGridView从未添加过新行。请告诉我，我该如何修复我的代码？
Thank you in advance.
先感谢您。
采纳答案by Aghilas Yakoub
You can try with this code - based on Rows.Add method
您可以尝试使用此代码 - 基于 Rows.Add method
DataTable table = new DataTable();
DataRow row = table.NewRow();
table.Rows.Add(row);
Link : https://msdn.microsoft.com/en-us/library/9yfsd47w.aspx
回答by rene
回答by Riccardo
try table.Rows.add(row);after your forstatement.
table.Rows.add(row);在你的for陈述之后尝试。
回答by x-silencer
This works for me:
这对我有用：
var table = new DataTable();
table.Rows.Add();
回答by Aleksey Kontsevich
If need to copy from another table then need to copy structure first:
如果需要从另一个表复制，则需要先复制结构：
DataTable copyDt = existentDt.Clone();
copyDt.ImportRow(existentDt.Rows[0]);
回答by Mehran Sarrafi
//?Creating a new row with the structure of the table:
//?用表的结构创建一个新行：
DataTable table = new DataTable();
DataRow row = table.NewRow();
table.Rows.Add(row);
//Giving values to the columns of the row(this row is supposed to have 28 columns):
//给行的列赋值（该行应该有 28 列）：
for (int i = 0; i < 28; i++)
{
row[i] = i.ToString();
}
回答by mimo
I found dotnetperls examples on DataRowvery helpful. Code snippet for new DataTablefrom there:
我发现dotnetperls 示例DataRow非常有帮助。DataTable来自那里的新代码片段：
static DataTable GetTable()
{
// Here we create a DataTable with four columns.
DataTable table = new DataTable();
table.Columns.Add("Weight", typeof(int));
table.Columns.Add("Name", typeof(string));
table.Columns.Add("Breed", typeof(string));
table.Columns.Add("Date", typeof(DateTime));
// Here we add five DataRows.
table.Rows.Add(57, "Koko", "Shar Pei", DateTime.Now);
table.Rows.Add(130, "Fido", "Bullmastiff", DateTime.Now);
table.Rows.Add(92, "Alex", "Anatolian Shepherd Dog", DateTime.Now);
table.Rows.Add(25, "Charles", "Cavalier King Charles Spaniel", DateTime.Now);
table.Rows.Add(7, "Candy", "Yorkshire Terrier", DateTime.Now);
return table;
}
回答by LollyPop
GRV.DataSource = Class1.DataTable;
GRV.DataBind();
Class1.GRV.Rows[e.RowIndex].Delete();
GRV.DataSource = Class1.DataTable;
GRV.DataBind();
