Spring Boot Rest Controller如何返回不同的HTTP状态码?
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Spring Boot Rest Controller how to return different HTTP status codes?
提问by Marco
I am using Spring Boot for a simple REST API and would like to return a correct HTTP statuscode if something fails.
我正在将 Spring Boot 用于一个简单的 REST API,并希望在出现故障时返回正确的 HTTP 状态码。
@RequestMapping(value="/rawdata/", method = RequestMethod.PUT)
@ResponseBody
@ResponseStatus( HttpStatus.OK )
public RestModel create(@RequestBody String data) {
// code ommitted..
// how do i return a correct status code if something fails?
}
Being new to Spring and Spring Boot, the basic question is how do i return different status codes when something is ok or fails?
作为 Spring 和 Spring Boot 的新手,基本问题是当某些事情正常或失败时我如何返回不同的状态代码?
回答by Jakub Kubrynski
There are several options you can use. Quite good way is to use exceptions and class for handling called @ControllerAdvice
:
您可以使用多个选项。很好的方法是使用异常和类来处理调用@ControllerAdvice
:
@ControllerAdvice
class GlobalControllerExceptionHandler {
@ResponseStatus(HttpStatus.CONFLICT) // 409
@ExceptionHandler(DataIntegrityViolationException.class)
public void handleConflict() {
// Nothing to do
}
}
Also you can pass HttpServletResponse
to controller method and just set response code:
您也可以传递HttpServletResponse
给控制器方法并设置响应代码:
public RestModel create(@RequestBody String data, HttpServletResponse response) {
// response committed...
response.setStatus(HttpServletResponse.SC_ACCEPTED);
}
Please refer to the this great blog post for details: Exception Handling in Spring MVC
有关详细信息,请参阅这篇很棒的博文:Spring MVC 中的异常处理
NOTE
笔记
In Spring MVC using @ResponseBody
annotation is redundant - it's already included in @RestController
annotation.
在 Spring MVC 中使用@ResponseBody
注解是多余的——它已经包含在@RestController
注解中。
回答by Ankit Basarkar
One of the way to do this is you can use ResponseEntity as a return object.
一种方法是您可以使用 ResponseEntity 作为返回对象。
@RequestMapping(value="/rawdata/", method = RequestMethod.PUT)
public ResponseEntity<?> create(@RequestBody String data) {
if(everything_fine)
return new ResponseEntity<>(RestModel, HttpStatus.OK);
else
return new ResponseEntity<>(null, HttpStatus.INTERNAL_SERVER_ERROR);
}
回答by Rodrigo Hernandez
Try this code:
试试这个代码:
@RequestMapping(value = "/validate", method = RequestMethod.GET, produces = "application/json")
public ResponseEntity<ErrorBean> validateUser(@QueryParam("jsonInput") final String jsonInput) {
int numberHTTPDesired = 400;
ErrorBean responseBean = new ErrorBean();
responseBean.setError("ERROR");
responseBean.setMensaje("Error in validation!");
return new ResponseEntity<ErrorBean>(responseBean, HttpStatus.valueOf(numberHTTPDesired));
}
回答by Vedant Goenka
In case you want to return a custom defined status code, you can use the ResponseEntity as here:
如果您想返回自定义定义的状态代码,您可以使用 ResponseEntity 如下:
@RequestMapping(value="/rawdata/", method = RequestMethod.PUT)
public ResponseEntity<?> create(@RequestBody String data) {
int customHttpStatusValue = 499;
Foo foo = bar();
return ResponseEntity.status(customHttpStatusValue).body(foo);
}
The CustomHttpStatusValue could be any integer within or outside of standard HTTP Status Codes.
CustomHttpStatusValue 可以是标准 HTTP 状态代码之内或之外的任何整数。