laravel 传递给 Illuminate\Auth\Guard::login() 的参数 1 必须实现接口 Illuminate\Auth\UserInterface，如果打开则为 null：
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Argument 1 passed to Illuminate\Auth\Guard::login() must implement interface Illuminate\Auth\UserInterface, null given open:
提问by user1072337
I have a Facebook login I am performing with OAuth2, and then I am using Laravel 4's built in Authentication system to log the user back in on revisit. For the majority of users, I see no issues with what I have, but for one user, he is seeing the following error appear on login:
我有一个使用 OAuth2 执行的 Facebook 登录，然后我使用 Laravel 4 的内置身份验证系统重新登录用户。对于大多数用户，我认为我拥有的内容没有问题，但对于一个用户，他在登录时看到以下错误：
ErrorException
Argument 1 passed to Illuminate\Auth\Guard::login() must implement interface Illuminate\Auth\UserInterface, null given
open: */nfs/c09/h04/mnt/139243/domains/crowdsets.com/vendor/laravel/framework/src/Illuminate/Auth/Guard.php
* /**
* Log a user into the application.
*
* @param \Illuminate\Auth\UserInterface $user
* @param bool $remember
* @return void
*/
public function login(UserInterface $user, $remember = false)
{
$id = $user->getAuthIdentifier();
Here is the relevant login/authentication code in the controller:
这是控制器中的相关登录/身份验证代码：
$check = Fan::where('fbid', '=', $user['uid'])->first();
if(is_null($check)) {
$fan = new Fan;
$fan->fbid = $user['uid'];
$fan->email = $user['email'];
$fan->first_name = $user['first_name'];
$fan->last_name = $user['last_name'];
$fan->gender = $user['gender'];
$fan->birthday = $user['birthday'];
$fan->age = $age;
$fan->city = $city;
$fan->state = $state_abbrev;
$fan->image = $user['image'];
$fan->friend_ids_url = $user['friends'];
$fan->friend_ids_unpacked = $friend_ids;
$fan->save();
$new = Fan::where('fbid', '=', $user['uid'])->first();
Auth::login($new);
return Redirect::to('fans/home');
}
else {
Auth::login($check);
$fan = Fan::find(Auth::user()->id);
$fan->image = $user['image'];
$fan->save();
return Redirect::to('fans/home');
var_dump($user);
}
This is my code in the model for the table I am using to keep user information, called "Fans":
这是我用来保存用户信息的表模型中的代码，称为“粉丝”：
<?php
use Illuminate\Auth\UserInterface;
class Fan extends Eloquent implements UserInterface {
protected $guarded = array();
public static $rules = array();
public function getAuthIdentifier()
{
return $this->getKey();
}
public function getAuthPassword()
{
return $this->password;
}
This is very perplexing because this login works for all of the other profiles I have tried. It is only with this friend's profile that it is throwing this error. I will also add, that on login (or retries) it will create multiple entries for this user in the database/table. This authentication system is supposed to be set up to prevent exactly this. Is there anything I'm missing?
这非常令人困惑，因为此登录适用于我尝试过的所有其他配置文件。只有这个朋友的个人资料才会抛出这个错误。我还要补充一点，在登录（或重试）时，它将在数据库/表中为该用户创建多个条目。应该设置此身份验证系统以防止发生这种情况。有什么我想念的吗？
回答by TheAngelM97
in the create() method in the LoginController you must return the $user that worked for me
在 LoginController 的 create() 方法中，您必须返回对我来说有效的 $user
protected function create(array $data)
{
$user = User::create([
'username' => $data['username'],
'email' => $data['email'],
'password' => bcrypt($data['password']),
]);
return $user;
}
回答by maxim.u
Try refactor your code to this:
尝试将您的代码重构为：
$fan = Fan::where('fbid', '=', $user['uid'])->first();
if (is_null($fan)) {
$fan = new Fan;
$fan->fbid = $user['uid'];
$fan->email = $user['email'];
$fan->first_name = $user['first_name'];
$fan->last_name = $user['last_name'];
$fan->gender = $user['gender'];
$fan->birthday = $user['birthday'];
$fan->age = $age;
$fan->city = $city;
$fan->state = $state_abbrev;
$fan->image = $user['image'];
$fan->friend_ids_url = $user['friends'];
$fan->friend_ids_unpacked = $friend_ids;
$fan->save();
} else {
$fan->image = $user['image'];
$fan->save();
}
Auth::loginUsingId($fan->getAuthIdentifier());
return Redirect::to('fans/home');
回答by Andreyco
Simple question and the answer:
Does your Fanclass extend Userclass (or implements UserInterface)?
If not, then the simplest way to fix this is
简单的问题和答案：
您的Fan类是否扩展了User类（或实现了UserInterface）？
如果没有，那么解决这个问题的最简单方法是
class Fan extends User{
....
}
回答by Nagibaba
try this. I solved my own.
尝试这个。我自己解决的。
$fan = User:where('id',$socialUser->getId())->first();
if(!$fan){
**$fan** = User:create([
'facebook_id' => $socialUser->getId(),
'email' => $socialUser->getEmail()
]);
auth()->login($fan);
return return->to('whereYouLike');
}
回答by Broski
I had the same issue and I managed to resolve it by checking few things:
我遇到了同样的问题，我通过检查几件事设法解决了它：
Argument 1 passed to Illuminate\Auth\Guard::login() must implement interface Illuminate\Auth\UserInterface, null given open:
Argument 1 passed to Illuminate\Auth\Guard::login() must implement interface Illuminate\Auth\UserInterface, null given open:
- As you can see,
null givenmeans that the$useryou want toAuth::login($user)is null. Check if the variable it set. - Don't put any
var_dump()between the Auth::login and the final redirect(). It may stop the Authentification.
- 如您所见，
null given意味着$user您想要的Auth::login($user)为空。检查它是否设置了变量。 - 不要
var_dump()在 Auth::login 和最终的 redirect() 之间放置任何东西。它可能会停止认证。
Hope it helps
希望能帮助到你
回答by devo
Instead of Auth::login($check);or Auth::login($new);you should pass,
而不是Auth::login($check);或者Auth::login($new);你应该通过，
Auth::login(Auth::user());
The Auth::login() function accept the first parameter as UserInterface Object like public function login(UserInterface $user, $remember = false)and in the function body, this will take useridlike this $id = $user->getAuthIdentifier();
Auth::login() 函数接受第一个参数作为 UserInterface 对象，就像public function login(UserInterface $user, $remember = false)在函数体中一样，这将userid是这样的$id = $user->getAuthIdentifier();
Read API Doc here.
在此处阅读 API 文档。
