Python 将另一个元组添加到元组的元组中
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Add another tuple to a tuple of tuples
提问by John
I have the following tuple of tuples:
我有以下元组元组：
my_choices=(
('1','first choice'),
('2','second choice'),
('3','third choice')
)
and I want to add another tuple to the start of it
我想在它的开头添加另一个元组
another_choice = ('0', 'zero choice')
How can I do this?
我怎样才能做到这一点？
the result would be:
结果将是：
final_choices=(
('0', 'zero choice')
('1','first choice'),
('2','second choice'),
('3','third choice')
)
采纳答案by Daniel Stutzbach
Build another tuple-of-tuples out of another_choice, then concatenate:
用 构建另一个元组元组another_choice，然后连接：
final_choices = (another_choice,) + my_choices
Alternately, consider making my_choicesa list-of-tuples instead of a tuple-of-tuples by using square brackets instead of parenthesis:
或者，考虑my_choices使用方括号而不是括号来制作元组列表而不是元组元组：
my_choices=[
('1','first choice'),
('2','second choice'),
('3','third choice')
]
Then you could simply do:
然后你可以简单地做：
my_choices.insert(0, another_choice)
回答by whaley
What you have is a tuple of tuples, not a list of tuples. Tuples are read only. Start with a list instead.
您拥有的是元组元组，而不是元组列表。元组是只读的。从列表开始。
>>> my_choices=[
... ('1','first choice'),
... ('2','second choice'),
... ('3','third choice')
... ]
>>> my_choices.insert(0,(0,"another choice"))
>>> my_choices
[(0, 'another choice'), ('1', 'first choice'), ('2', 'second choice'), ('3', 'third choice')]
list.insert(ind,obj) inserts obj at the provided index within a list... allowing you to shove any arbitrary object in any position within the list.
list.insert(ind,obj) 在列表中提供的索引处插入 obj ......允许您将任意对象推入列表中的任何位置。
回答by Katriel
Don't convert to a list and back, it's needless overhead. +concatenates tuples.
不要转换为列表并返回，这是不必要的开销。+连接元组。
>>> foo = ((1,),(2,),(3,))
>>> foo = ((0,),) + foo
>>> foo
((0,), (1,), (2,), (3,))
回答by Brendan
Alternatively, use the tuple concatenation
或者，使用元组连接
i.e.
IE
final_choices = (another_choice,) + my_choices
