如何从 Google Sign-In Javascript SDK 获取访问令牌?
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How to get the access token from Google Sign-In Javascript SDK?
提问by stickfigure
I have a simple single-page javascript webapp which uses "Google Sign-In for Websites": https://developers.google.com/identity/sign-in/web/sign-in
我有一个简单的单页 javascript webapp,它使用“Google 网站登录”:https: //developers.google.com/identity/sign-in/web/sign-in
How can I get an access token for the user? I need a verifiable assertion of the user's identity on my server. I don't want offline access; I just want to know that when the web client sends an ajax request to my server, I can trust the identity of the logged-in user.
如何获取用户的访问令牌?我需要在我的服务器上对用户身份进行可验证的断言。我不想离线访问;我只是想知道,当 web 客户端向我的服务器发送 ajax 请求时,我可以信任登录用户的身份。
回答by Scarygami
For verification purposes it would be better to use the id_token
which is part of the auth response, and can be retrieved at any point like this:
出于验证目的,最好使用id_token
auth 响应的一部分,并且可以像这样在任何时候检索:
gapi.auth2.getAuthInstance().currentUser.get().getAuthResponse().id_token
The Google API Client libraries offer functions to verify the id_token and give you the associated user information on the server side: https://developers.google.com/api-client-library/
Google API 客户端库提供了验证 id_token 并在服务器端为您提供相关用户信息的功能:https: //developers.google.com/api-client-library/
回答by Pravin Ghorle
Hope your are doing well. Here is the solution, You may try this: Actually there is no such a function name getAccessToken (Android Only) define in GoogleSignin.android.js as written here https://github.com/devfd/react-native-google-signin. But the best part is they have already implemented the solution in GoogleSignin.android.js. just take a look at the code below from GoogleSignin.android.js
希望你做得好。这是解决方案,您可以试试这个:实际上没有这样的函数名称 getAccessToken (Android Only) 在 GoogleSignin.android.js 中定义,如此处所写https://github.com/devfd/react-native-google-signin. 但最好的部分是他们已经在 GoogleSignin.android.js 中实现了解决方案。看看下面来自 GoogleSignin.android.js 的代码
currentUserAsync() {
return new Promise((resolve, reject) => {
const sucessCb = DeviceEventEmitter.addListener('RNGoogleSignInSilentSuccess', (user) => {
this._user = user;
RNGoogleSignin.getAccessToken(user).then((token) => {
this._user.accessToken = token;
this._removeListeners(sucessCb, errorCb);
resolve(this._user);
})
.catch(err => {
this._removeListeners(sucessCb, errorCb);
resolve(this._user);
});
});
The thing is only we have do use this code wisely. I have use the below code to get access_token and it help me to solve my access token problem. I change above function like this in GoogleSignin.android.js
问题是我们必须明智地使用此代码。我使用下面的代码来获取 access_token,它帮助我解决了我的访问令牌问题。我在 GoogleSignin.android.js 中像这样更改了上述功能
currentUserAsync() {
return new Promise((resolve, reject) => {
const sucessCb = DeviceEventEmitter.addListener('RNGoogleSignInSilentSuccess', (user) => {
this._user = user;
RNGoogleSignin.getAccessToken(user).then((token) => {
this._user.accessToken = token;
this._removeListeners(sucessCb, errorCb);
resolve(token);
})
.catch(err => {
this._removeListeners(sucessCb, errorCb);
resolve(this._user);
});
});
and I call this function like this from index.android.js.
我从 index.android.js 中这样调用这个函数。
_signIn() {
GoogleSignin.signIn()
.then((user) => {
console.log('this1' + JSON.stringify(user));
this.setState({user: user});
var gettoken = GoogleSignin.currentUserAsync(user).then((token) => {
console.log('USER token', token);
this.setState({user: user});
}).done();
}).catch((err) => {
console.log('WRONG SIGNIN', err);
})
.done();
}
You can call it as a individual function it look like this. in GoogleSignin.android.js
您可以将其作为一个单独的函数调用,它看起来像这样。在 GoogleSignin.android.js 中
getAccessTok(user)
{
RNGoogleSignin.getAccessToken(user).then((token) => {
this._user.accessToken = token;
resolve(token);
})
.catch(err => {
this._removeListeners(sucessCb, errorCb);
console.log('got error');
resolve(this._user);
});
}
and from index.android.js just call this function like this
并从 index.android.js 像这样调用这个函数
_getToken(){
console.log(GoogleSignin.getAccessTok(this.state.user));
}
only you have to do is to pass the current user to get access token. Hope this will help you.Have a great day.Thank You.
你唯一要做的就是通过当前用户来获取访问令牌。希望这会帮助你。祝你有美好的一天。谢谢。