javascript jquery中字母数字和特殊字符的正则表达式
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/8411001/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Regex for alphanumeric and special characters in jquery
提问by jogesh_pi
i tried to make a regex for my Address column the code is:
我试图为我的地址列创建一个正则表达式，代码是：
var str = "97sadf []#-.'";
var regx = /^[a-zA-z0-9\x|]|[|-|'|.]*$/;
if(str.match(regx))
document.write('Correct!');
else
document.write('Incorrect!');
the special character i want that is ][#-.the given code return me the correct match but if i add another kind of the special character like @%then the correct result i got, but i want the incorrect result.
我想要的特殊字符是][#-.给定的代码，返回正确的匹配，但如果我添加另一种特殊字符，就像@%我得到的正确结果，但我想要不正确的结果。
i don't know where i did wrong please help me to make right..
我不知道我哪里做错了请帮我改正..
EDIT: Sorry guys but the one thing i have to discuss with you that is there is no necessary to enter the special characters that i mentioned ][#-., but if the someone enter other then the given special character then should return the incorrect.
编辑：对不起，伙计们，但我必须与你们讨论的一件事是没有必要输入我提到的特殊字符][#-.，但是如果有人输入其他给定的特殊字符，则应该返回不正确的字符。
回答by mynameiscoffey
The correct regex (assuming you want uppercase letters, lowercase letters, numbers, spaces and special characters [].-#') is:
正确的正则表达式（假设您需要大写字母、小写字母、数字、空格和特殊字符[].-#'）是：
var regx = /^[a-zA-Z0-9\s\[\]\.\-#']*$/
There are a couple things breaking your code.
有几件事会破坏您的代码。
First, [, ], -and .have special meaning, and must be escaped (prefixed with \).
首先, [, ], -and.有特殊含义，必须转义（以 为前缀\）。
\xchecks for line breaks, where we want spaces (\s).
\x检查换行符，我们需要空格 ( \s)。
Next, lets look at the structure; for simplicity's sake, lets simplify to ^[abc]|[def]*$. (abcand defbeing your two blocks of character types). Since the *is attached to the second block, it is saying one instance of [abc]or any number of [def].
接下来，让我们看一下结构；为简单起见，让我们简化为^[abc]|[def]*$。（abc并def成为您的两个字符类型块）。由于*附加到第二个块，它表示 的一个实例[abc]或任意数量的[def]。
Finally, we don't need |inside of brackets, becuase they already mean one character contained within them (already behaves like an or).
最后，我们不需要|括号内，因为它们已经表示包含在其中的一个字符（已经表现得像一个或）。
