MySQL 中两个时间字段的分钟数差异

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时间:2020-08-31 18:51:35  来源:igfitidea点击:

Difference in minutes from two time fields in MySQL

mysqltime

提问by NeilG

I set up my MySQL database with the field 'time'

我使用字段“时间”设置了我的 MySQL 数据库

It is not HH:MM in the traditional sense, it is the time an event occurred, so an event with the value of 5:45 occurred with 5 minutes 45 seconds left in a game. 12:25 occurred with 12 minutes and 25 seconds left, etc.

它不是传统意义上的 HH:MM,它是一个事件发生的时间,所以一个值为 5:45 的事件在比赛还剩 5 分 45 秒时发生。12:25 发生,还有 12 分 25 秒,等等。

I would like to be able to find out the total time elapsed, so if I have an event that occurred at 12:25 and the next event occurred at 5:45 I want to be able to get the difference, which would be equal to 6:40. Then, I would like to express this as a decimal, in this case 6.67.

我希望能够找出经过的总时间,所以如果我有一个发生在 12:25 的事件而下一个事件发生在 5:45 我希望能够得到差异,这将等于6:40。然后,我想将其表示为小数,在本例中为 6.67。

Is this possible?

这可能吗?

Thanks in advance.

提前致谢。

回答by Shawn

Just use

只需使用

TIMEDIFF(fromtime, totime):

SELECT TIMEDIFF("12:25", "5:45");

If you need a decimal, use TIME_TO_SEC()/3600(it assumes you passed it seconds, but the format you're storing the times in is vague and SQL probably will interpret them as HH:MM - you can fix this with CONCAT("00:",MinuteSecondField)maybe?) - then you can use TIME_TO_SEC()/60, which is more correct)

如果您需要小数,请使用TIME_TO_SEC()/3600(它假设您传递了秒数,但是您存储时间的格式是模糊的,SQL 可能会将它们解释为 HH:MM - 您可以用CONCAT("00:",MinuteSecondField)也许解决这个问题?) - 那么您可以使用TIME_TO_SEC()/60,这是更正确的)

回答by A T

回答by artfulrobot

I needed similar. Two useful functions: TIME_TO_SECand SUBTIME.

我需要类似的。两个有用的功能:TIME_TO_SECSUBTIME

e.g. if your time fields were normal HH:MM times, then

例如,如果您的时间字段是正常的 HH:MM 时间,那么

SELECT (TIME_TO_SEC(end_time) - TIME_TO_SEC(start_time))/60 AS `minutes` 

In your case, as I understand it, the times are backwards, ie. 12:00<6:00so your end_time and start_time would need swapping.

在你的情况下,据我所知,时代是倒退的,即。12:00<6:00所以你的 end_time 和 start_time 需要交换。

If you wanted the output in HH:MM:SS you could do

如果你想要 HH:MM:SS 的输出,你可以这样做

SELECT SUBTIME(end_time, start_time)

回答by Alex Pakka

I used UNIX_TIMESTAMP(event1)-UNIX_TIMESTAMP(event2), which gives you seconds between events. Divide it by 60.0 and you will get a decimal as per your requirement. This solution assumes, your columns are date-compatible values. It will work really fast if they are TIMESTAMPs.

我使用了 UNIX_TIMESTAMP(event1)-UNIX_TIMESTAMP(event2),它为您提供了事件之间的秒数。将其除以 60.0,您将根据您的要求得到一个小数。此解决方案假定您的列是日期兼容的值。如果它们是 TIMESTAMP,它会工作得非常快。

UPDATE: This solution only works with timestamp data types, not time datatypes as in original question.

更新:此解决方案仅适用于时间戳数据类型,而不适用于原始问题中的时间数据类型。