C语言 在 C 中逐字符读取字符串
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/26072322/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Reading string character by character in C
提问by aNobody
So I have a string passed into main function: int main(int argc, char* argv[])
所以我有一个字符串传递给主函数： int main(int argc, char* argv[])
I understand argc (which is 2 in this case), but don't understand how I can read argv[] character by character? When I print argv[0] shouldn't that print the first character in the array of characters for that string?
我了解 argc（在本例中为 2），但不明白我如何逐个读取 argv[] ？当我打印 argv[0] 时，不应该打印该字符串的字符数组中的第一个字符吗？
Thanks
谢谢
回答by BLUEPIXY
sample
样本
#include <stdio.h>
int main(int argc, char *argv[]){
int i,j;
for(i=0; i<argc; ++i){
for(j=0; argv[i][j] != '#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main (int argc, char *argv[])
{
if(argc != 2)
{
//argv[0] is name of executable
printf("Usage: %s argument\n", argv[0]);
exit(1);
}
else
{
int i;
int length = strlen(argv[1]);
for(i=0;i<length;i++)
{
printf("%c",argv[1][i]);
}
printf("\n");
return 0;
}
}
'; ++j){
printf("(%c)", argv[i][j]);
}
printf("\n");
}
return 0;
}
回答by user1336087
One more example:
再举一个例子：
##代码##