javax.naming.NameNotFoundException: [LDAP: 错误代码 32 - 没有这样的对象]; 剩余名称 'dc=server,dc=lan,cn=admin'
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javax.naming.NameNotFoundException: [LDAP: error code 32 - No Such Object]; remaining name 'dc=server,dc=lan,cn=admin'
提问by user3278647
Am new to LDAP and am trying to use it for authentication. But i keep on getting this error: Connection Successful.
我是 LDAP 的新手，正在尝试使用它进行身份验证。但我不断收到此错误：连接成功。
[LDAP: error code 32 - No Such Object]
javax.naming.NameNotFoundException: [LDAP: error code 32 - No Such Object]; remaining name 'dc=server,dc=lan,cn=admin'
at com.sun.jndi.ldap.LdapCtx.mapErrorCode(LdapCtx.java:3112)
at com.sun.jndi.ldap.LdapCtx.processReturnCode(LdapCtx.java:3033)
at com.sun.jndi.ldap.LdapCtx.processReturnCode(LdapCtx.java:2840)
at com.sun.jndi.ldap.LdapCtx.searchAux(LdapCtx.java:1849)
at com.sun.jndi.ldap.LdapCtx.c_search(LdapCtx.java:1772)
at com.sun.jndi.toolkit.ctx.ComponentDirContext.p_search(ComponentDirContext.java:386)
at com.sun.jndi.toolkit.ctx.PartialCompositeDirContext.search(PartialCompositeDirContext.java:356)
at com.sun.jndi.toolkit.ctx.PartialCompositeDirContext.search(PartialCompositeDirContext.java:339)
at javax.naming.directory.InitialDirContext.search(InitialDirContext.java:267)
at ldap.Fedora.one(Fedora.java:104)
at ldap.Fedora.main(Fedora.java:67)
This is where i have reached so far:
这是我到目前为止到达的地方：
Hashtable<String, Object> env = new Hashtable<String, Object>();
env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
env.put(Context.PROVIDER_URL, "ldap://localhost:389/dc=server,dc=lan");
env.put(Context.SECURITY_AUTHENTICATION, "simple");
env.put(Context.SECURITY_PRINCIPAL, "cn=admin,dc=server,dc=world");
env.put(Context.SECURITY_CREDENTIALS, "william");
DirContext context = null;
NamingEnumeration namingEnumeration = null;
try {
context = new InitialDirContext(env);
System.out.println("Connection Successful.");
SearchControls controls = new SearchControls();
controls.setSearchScope(SearchControls.SUBTREE_SCOPE);
namingEnumeration = context.search("dc=server,dc=lan,cn=admin", "objectClass=posixGroup", controls);
while (namingEnumeration.hasMore()) {
SearchResult searchResult = (SearchResult) namingEnumeration.next();
Attributes attributes = searchResult.getAttributes();
Attribute attr = attributes.get("cn");
String cn = (String) attr.get();
System.out.println(" Person Common Name = " + cn);
}
} catch (Exception e) {
System.out.println(e.getMessage());
e.printStackTrace();
} catch (Throwable e) {
e.printStackTrace();
} finally {
if (namingEnumeration != null) {
try {
namingEnumeration.close();
} catch (Exception e) {
}
}
if (context != null) {
try {
context.close();
} catch (Exception e) {
}
}
}
回答by Thomas Kl?ger
The error message means that the object "dc=server,dc=lan,cn=admin" cannot be found.
错误信息表示找不到对象“dc=server,dc=lan,cn=admin”。
Your search base should probably be "cn=admin,dc=server,dc=lan"
您的搜索基础应该是“cn=admin,dc=server,dc=lan”
回答by Ashok Parmar
For example using https://www.forumsys.com/tutorials/integration-how-to/ldap/online-ldap-test-server/
例如使用https://www.forumsys.com/tutorials/integration-how-to/ldap/online-ldap-test-server/
if LDAP username is not valid set then also shows 32 error.
如果 LDAP 用户名设置无效，则还会显示 32 错误。
below are the properties for reference
以下是可供参考的属性
- ldap.urls=ldap://ldap.forumsys.com:389/
- ldap.base.dn=cn=read-only-admin,dc=example,dc=com
- ldap.password=password
- ldap.username=dc=example,dc=com
- ldap.user.dn.pattern =uid={username},ou=scientists,dc=example,dc=com
- ldap.aut.domain=ashokParmar
- ldap.urls=ldap://ldap.forumsys.com:389/
- ldap.base.dn=cn=read-only-admin,dc=example,dc=com
- ldap.password=密码
- ldap.username= dc=example,dc=com
- ldap.user.dn.pattern =uid={username},ou=scientists,dc=example,dc=com
- ldap.aut.domain=ashokParmar
