Python 将 BytesIO 转换为文件
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Convert BytesIO into File
提问by K Engle
I have a BytesIO object containing the data of an excel document. The library I want to use doesn't support BytesIO and expects a File object instead. How can I take my BytesIO object and convert it into a File object?
我有一个包含 excel 文档数据的 BytesIO 对象。我想使用的库不支持 BytesIO，而是需要一个 File 对象。如何获取 BytesIO 对象并将其转换为 File 对象？
采纳答案by Reid Ballard
So, it would be a lot more helpful if you supplied the library you were using to work on excel files, but here's a buckshot of solutions, some of which may work, based on random assumptions I'm making due to complete lack of sample code:
因此，如果您提供用于处理 excel 文件的库会更有帮助，但这里有一些解决方案，其中一些可能有效，基于我由于完全缺乏样本而做出的随机假设代码：
- Based on the first paragraph in the io module, it sounds like all the concrete classes- including BytesIO- are file-like objects. Without knowing what code you've tried so far, I don't know if you tried just passing the BytesIO to whatever module you're using.
- On the off chance that doesn't work, you can simply convert BytesIO to a another io Writer/Reader/Wrapper by passing it to the constructor. Example:
- 基于io 模块中的第一段，听起来所有具体的类——包括 BytesIO——都是类文件对象。在不知道到目前为止您尝试过哪些代码的情况下，我不知道您是否尝试将 BytesIO 传递给您正在使用的任何模块。
- 如果不起作用，您可以简单地将 BytesIO 转换为另一个 io Writer/Reader/Wrapper，方法是将其传递给构造函数。例子：
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import io
b = io.BytesIO(b"Hello World") ## Some random BytesIO Object
print(type(b)) ## For sanity's sake
with open("test.xlsx") as f: ## Excel File
print(type(f)) ## Open file is TextIOWrapper
bw=io.TextIOWrapper(b) ## Conversion to TextIOWrapper
print(type(bw)) ## Just to confirm
- You may need to check which kind of Reader/Writer/Wrapper is expected by the module you're using to convert the BytesIO to the correct one
- I believe I have heard that (for memory reasons, due to extremely large excel files) excel modules do not load the entire file. If this ends up meaning that what you need is a physical file on the disk, then you can easily write the Excel file temporarily and just delete it when you're done. Example:
- 您可能需要检查您用于将 BytesIO 转换为正确的模块需要哪种类型的 Reader/Writer/Wrapper
- 我相信我听说过（出于内存原因，由于 excel 文件非常大）excel 模块不会加载整个文件。如果这最终意味着您需要的是磁盘上的物理文件，那么您可以轻松地临时编写 Excel 文件，并在完成后将其删除。例子：
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import io
import os
with open("test.xlsx",'rb') as f:
g=io.BytesIO(f.read()) ## Getting an Excel File represented as a BytesIO Object
temporarylocation="testout.xlsx"
with open(temporarylocation,'wb') as out: ## Open temporary file as bytes
out.write(g.read()) ## Read bytes into file
## Do stuff with module/file
os.remove(temporarylocation) ## Delete file when done
I'll hope that one of these points will solve your problem.
我希望这些要点之一可以解决您的问题。
回答by Martin Thoma
# Create an example
from io import BytesIO
bytesio_object = BytesIO(b"Hello World!")
# Write the stuff
with open("output.txt", "wb") as f:
f.write(bytesio_object.getbuffer())
回答by johnson
pathlib.Path('file').write_bytes(io.BytesIO(b'data').getbuffer())
